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4
Joe Oberbrunner
Samantha Wetterlund
y=2y+x
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Does this system of equations have one solution no solutions or an infinite number of solutions x - 2y equals -6 and x-2y equals 2?
x - 2y = -6 x - 2y = 2 subtract the 2nd equation from the 1st equation 0 = -8 false Therefore, the system of the equations has no solution.
How do you graph the equation x plus 2y equals 4?
First, write out the problem: x+2y=4 then you have to simplify it so that only y is on one side x+2y=4 -4 -4 x+2y-4=0 -2y -2y x-4=-2y / -2 = -1/2x + 2 = y then, draw out a graph: and, let's say, x=4, then you plug that into the equation, and solve for y in this case, if x=4, then y=0, so one of the points would be (4, 0)
Is point 2 -3 on the line represented by the equation x - 2y -4?
No
Solve x equal 2y and y equal x minus 2?
x = 2y y = x - 2 or x = 2y subtract 2y to both sides x - 2 = y subtract y and add 2 to both sides x - 2y = 0 multiply by -1 to both sides x - y = 2 -x + 2y = 0 x - y = 2 add these two equations together y = 2 substitute 2 for y into the first equation, x = 2y x = 2(2) = 4 Thus the solution of these linear system of equations is the point (4, 2). Check:
Rewrite the equation 5x-2y0 in slope-intercept form?
5x - 2y = 05x - 5x - 2y = 0 - 5x-2y = - 5x(-2y)/-2 = (-5x)/-2y = (5/2)x where the slope is 5/2 and the y-intercept is 0.
What is the x in the equation -x2 plus 3x plus 2y?
This is only half of an equation. If -x^2 + 3x +2y = 0, then x^2 -3x = 2y and y = (x^2-3x)/2 Solving for x is the inverse, but difficult without a second equation.
How do you the solve the equation x equals 2y in terms of x?
To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.
Is point 1 4 on the line represented by the equation x plus 2y equals 5?
The equation "x plus 2y equals 5" is: x + 2y = 5 2y = 5 - x y = 5/2 - 1/2x y = -1/2x + 5/2
Does this system of equations have one solution no solutions or an infinite number of solutions x - 2y equals -6 and x-2y equals 2?
x - 2y = -6 x - 2y = 2 subtract the 2nd equation from the 1st equation 0 = -8 false Therefore, the system of the equations has no solution.
Is point 1 2 on the line represented by the equation x 2y 5?
If you mean x+2y = 5 then yes
What does x equal in this equation- 4-2y plus 2?
Since there is no x in the equation, it can equal anything at all!
What is the slope of the line represented by the equation x plus 2y equals 1?
x+2y = 1 2y = -x+1 y = -1/2x+1/2 Slope = -1/2 and the intercept is 1/2
Solve this equation using subtitution x equals 4y and 3x-2y equals 20?
3x - 2y = 20 Substitute x = 4y into this equation: 3(4y) - 2y = 20 ie 12y - 2y = 20 10y = 20 so that y = 2 and then x = 4y gives x = 2*4 = 8
Where does x equals 9-2y and x plus 2y equals 13 intersect on a graph?
first get both your equations into standard form... x + 2y = 9 (equation 1) x + 2y = 13 (equation 2) multiply equation 1 by (-1) -x - 2y = -9 x + 2y = 13 add the equations together 0 + 0 = 4 0 = 4 since the equations dont equal out then these equations do not intersect and are therefore parallel. PARALLEL is your answer
Solve this equation using subtitution x plus 2y equals 7 and 2x plus y equals 8?
x + 2y = 7 So x = 7 - 2y Substitute this value for x in the second equation which then is: 2(7 - 2y) + y = 8 Simplify: 14 - 4y + y = 8 -3y = -6 y = 2 Put this value of y back into the first equation: x + 2*2 = 7 ie x + 4 = 7 x = 3
How do you graph the equation x plus 2y equals 4?
First, write out the problem: x+2y=4 then you have to simplify it so that only y is on one side x+2y=4 -4 -4 x+2y-4=0 -2y -2y x-4=-2y / -2 = -1/2x + 2 = y then, draw out a graph: and, let's say, x=4, then you plug that into the equation, and solve for y in this case, if x=4, then y=0, so one of the points would be (4, 0)
Can you solve x plus 2y equals 2?
No. There is not enough information in the equation x + 2y = 2, by itself, to solve it. There are an infinite number of solutions. A second equation, or information to allow a second equation to be derived, must be given to find a solution.
