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Does this system of equations have one solution no solutions or an infinite number of solutions x - 2y equals -6 and x-2y equals 2?
x - 2y = -6 x - 2y = 2 subtract the 2nd equation from the 1st equation 0 = -8 false Therefore, the system of the equations has no solution.
How do you graph the equation x plus 2y equals 4?
First, write out the problem: x+2y=4 then you have to simplify it so that only y is on one side x+2y=4 -4 -4 x+2y-4=0 -2y -2y x-4=-2y / -2 = -1/2x + 2 = y then, draw out a graph: and, let's say, x=4, then you plug that into the equation, and solve for y in this case, if x=4, then y=0, so one of the points would be (4, 0)
Solve x equal 2y and y equal x minus 2?
x = 2y y = x - 2 or x = 2y subtract 2y to both sides x - 2 = y subtract y and add 2 to both sides x - 2y = 0 multiply by -1 to both sides x - y = 2 -x + 2y = 0 x - y = 2 add these two equations together y = 2 substitute 2 for y into the first equation, x = 2y x = 2(2) = 4 Thus the solution of these linear system of equations is the point (4, 2). Check:
Is point 2 -3 on the line represented by the equation x - 2y -4?
No
Rewrite the equation 5x-2y0 in slope-intercept form?
5x - 2y = 05x - 5x - 2y = 0 - 5x-2y = - 5x(-2y)/-2 = (-5x)/-2y = (5/2)x where the slope is 5/2 and the y-intercept is 0.
