x = 2y
y = x - 2 or
x = 2y subtract 2y to both sides
x - 2 = y subtract y and add 2 to both sides
x - 2y = 0 multiply by -1 to both sides
x - y = 2
-x + 2y = 0
x - y = 2 add these two equations together
y = 2 substitute 2 for y into the first equation, x = 2y
x = 2(2) = 4
Thus the solution of these linear system of equations is the point (4, 2).
Check:
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
To solve the given terms is almost impossible in the absence of any plus, minus and equality signs.
2y = 4 (divide both sides by 2 to solve) y = 2
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
(2y - 5)(y - 2)
5m + 7 - 2m - 1 = 3m + 6
5/2
2y
If you mean: -2y-3-y+2 then it can be simplified to -1-3y
2y = 15 y = 15/2 y = 7.5
2y = 4x + 4y = 2x + 2
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2