x = 2y
y = x - 2 or
x = 2y subtract 2y to both sides
x - 2 = y subtract y and add 2 to both sides
x - 2y = 0 multiply by -1 to both sides
x - y = 2
-x + 2y = 0
x - y = 2 add these two equations together
y = 2 substitute 2 for y into the first equation, x = 2y
x = 2(2) = 4
Thus the solution of these linear system of equations is the point (4, 2).
Check:
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
The solutions are: x = -2 and y = 4
2y - 9x = 14 2y = 14 + 9x y = (14 + 9x) / 2
Eliminate the variables that have equal coefficients but opposite in sign.x + 2y = 103x - 2y = 14Or you can work to have one of the variables with equal coefficients but opposite in sign such as:3x + 2y = 5x + y = 2 multiply by -2 to both sides3x + 2y = 5-2x - 2y = -4
-2 or negative 2
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
To solve the given terms is almost impossible in the absence of any plus, minus and equality signs.
2y = 4 (divide both sides by 2 to solve) y = 2
5m + 7 - 2m - 1 = 3m + 6
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
(2y - 5)(y - 2)
5/2
If you mean: -2y-3-y+2 then it can be simplified to -1-3y
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. If your question is not answered, please resubmit it, spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (x^2) or x-squared.Restate the question: Solve for y: 2y = y+2Subtract y from both sides: 2y-y = y-y+2 y=2
2y = 4x + 4y = 2x + 2
2y = 15 y = 15/2 y = 7.5
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2