0
x = 2y
y = x - 2 or
x = 2y subtract 2y to both sides
x - 2 = y subtract y and add 2 to both sides
x - 2y = 0 multiply by -1 to both sides
x - y = 2
-x + 2y = 0
x - y = 2 add these two equations together
y = 2 substitute 2 for y into the first equation, x = 2y
x = 2(2) = 4
Thus the solution of these linear system of equations is the point (4, 2).
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How do you solve x squared minus 2x minus 4y squared minus 4y?
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
Solve the following system of equations express your answer as an ordered pair 2x plus 5y equals 16 and -5x minus 2y equals 2?
The solutions are: x = -2 and y = 4
2y-9x equals 14 solve for y?
2y - 9x = 14 2y = 14 + 9x y = (14 + 9x) / 2
What is the key to using the elimination method to find variable terms in the two equations that have equal or opposite coefficients?
Eliminate the variables that have equal coefficients but opposite in sign.x + 2y = 103x - 2y = 14Or you can work to have one of the variables with equal coefficients but opposite in sign such as:3x + 2y = 5x + y = 2 multiply by -2 to both sides3x + 2y = 5-2x - 2y = -4
What does 0 minus 2 equal?
-2 or negative 2
