That of course will depend entirely on the straight line equation which has not been given but in general in the equation y = mx+b the slope is m and b is the y intercept
5
There is a standard equation for a straight line. It is y = mx + b. m is the slope and b is the y-intercept (when x = 0). In the question m = -4 and is therefore the slope of the line represented by the equation y = -4x + 7.
A line with no slope is a vertical line. The slope is undefined, and cannot be represented by a real number. A horizontal line has a slope, but the slope is zero. Consider the "y = mx + b" form of the straight line equation. For a horizontal line the slope is zero, so y = 0x +b => y = b, which is the equation of a horizontal line. For a vertical line, there is no slope, so you can't substitute for m; the equation can't be written in the form y = mx +b. The equation of a vertical line has the form x = a.
Literal equation refers to an equation in which the variables represent known values. This type of equation allows the representation of things like distance, interest, time, and slope as variables in an equation.
The slope is -4
The slope is -0.2
There is no "equals" sign therefore "x-9" is NOT an equation.
The slope of this equation is 10 and the y intercept is 150
x = -3 represents a vertical line whose slope is undefined.
That of course will depend entirely on the straight line equation which has not been given but in general in the equation y = mx+b the slope is m and b is the y intercept
5
Without an equality sign it is not an equation but when a straight line equation is parallel to another straight line the slope remains the same but the y intercept is different
The equation, y = -4x - 3, is written in what's called slope-intercept form. The general equation for slope-intercept form is y = mx + b, where m is the slope of the line, and b is the y-intercept. So, for the equation in question, m = -4 and b = -3. Thus, the slope of the line is -4.
Slope :)
-1/5
q2