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Let the numbers be ,n, n+2, n+4, & n+6

Hence

n + (n+2) + (n+4)+(n + 6) = 92

Add the LHS

4n + 12 = 92

4n = 92 - 12 = 80

4n = 80

n = 20

Hence

n+2 = 20 + 2 = 22

n_4 = 20+4 = 24

n+6 = 20 + 6 = 26

Hencce the four even consecutive numbers are 20,22,24, & 26.

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lenpollock

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8mo ago

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Related Questions

What four consecutive even numbers have the sum of 92?

The numbers are 20, 22, 24 and 26.


Consecutive even numbers that have the sum of 186?

Let's represent the first even number as x. The next consecutive even number would be x + 2. Since they are consecutive even numbers, their sum can be expressed as x + (x + 2) = 186. Simplifying this equation, we get 2x + 2 = 186. Solving for x, we find x = 92. Therefore, the consecutive even numbers are 92 and 94.


What are two consecutive numbers for 186?

There are two consecutive even numbers. The numbers are 92 and 94.


Find for consecutive numbers with the sum of -362?

-89, -90, -91, -92


What are 4 consecutive numbers that sum to 374?

They are: 92+93+94+95 = 374


What 3 consecutive odd numbers total 270?

The sum of two odd numbers is even and the sum of an even number and an odd number is odd.So the sum of three consecutive odd numbers is odd but 270 is even.Ergo there are no three consecutive odd numbers that sum to 270.Three consecutive numbers that sum to 270 are 89, 90, 91.Three consecutive even numbers that sum to 270 are 88, 90, 92.


What are 2 consecutive numbers that are equal to 182?

There are two consecutive even integers: 90 and 92.


The sum of four consecutive integers is -92 what are the four integers?

This is impossible with positive integers. However, four numbers separated by a difference of 1 with a sum of -92 are: -21.5 -22.5 -23.5 -24.5


How do you make 92 with consecutive numbers?

To make 92 with consecutive numbers, you can use the formula for the sum of an arithmetic series: n/2 * (first number + last number) = 92. Since we are looking for consecutive numbers, the first number can be 45 and the last number can be 47. Plugging these values into the formula, we get 3/2 * (45 + 47) = 3/2 * 92 = 92, so the consecutive numbers 45, 46, and 47 add up to 92.


The sum of three consecutive integers is 279?

x + x + 1 + x + 2 = 279 3x + 3 = 279 3x = 279 - 3 = 276 x = 92 Hence the three consecutive numbers are 92, 93, and 94


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They are: 92+93+94+95 = 374


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