There are many possible answers but the simplest is
|x + 2| = 8
You can write this as two equations, and solve them separately. The two equations are:x - 19 = -3and:-x - 19 = -3
In math a normal absolute value equations share a vertex.
On a number line does 2 or - 2 represent the absolute value of -2?
The part that is shaded represents all the possible solutions. An inequality has solutions that are either left or righ, above or below or between two parts of a graph.
The absolute value of somthing is the distance a number is from zero. Absolute value sign- is two lines going vertical up and down example - l (number) l l-7l the absolute value of -7 would be 7 because -7 is 7 places away from zero.
What's your question? To solve an absolute value inequality, knowledge of absolute values and solving inequalities are necessary. Absolute value inequalities can have one or two variables.
They each typically have two solutions, a positive one and a negative one.
To write and solve an absolute value inequality, start by expressing the inequality in the form |x| < a or |x| > a, where a is a positive number. For |x| < a, split it into two inequalities: -a < x < a. For |x| > a, split it into two separate inequalities: x < -a or x > a. Finally, solve each inequality to find the solution set and represent it using interval notation or a number line.
Infinite.
You can write this as two equations, and solve them separately. The two equations are:x - 19 = -3and:-x - 19 = -3
The absolute value of the sum of two complex numbers is less than or equal to the sum of their absolute values.
Infinitely many.
whats the absolute value of positive two thirds
x>|7| + |8|
Two cases in which this can typically happen (there are others as well) are: 1. The equation includes a square. Example: x2 = 25; the solutions are 5 and -5. 2. The equation includes an absolute value. Example: |x| = 10; the solutions are 10 and -10.
NO! abs(2-2)=0 NOT equal to abs(2)+abs(-2)=4 - The above is technically correct, though the more thorough answer is as follows; no because the absolute value of the sum is LESS THEN OR EQUAL TO the sum of the absolute values. The simple proof the the fact that |A+B|<=|A|+|B| is called the triangular inequality. When A and B (or for that matter an infinite number of them) are both positive (or all) or both negative (or all) then they inequality is actually equal, if however any of the numbers have different signs then any other number, the inequality is less then.
No, an absolute value must be non-negative.