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|x|=√(x^2).
I would do it that way.
The expression (a+b) + (a-b) can be rewritten as a + b + a - b = 2a.There is no need to use absolute value.
| 2x + 3 | = 11 make 2 cases case 1) 2x + 3 = 11; solve x = 4 case 2) 2x + 3 = -11; solve x = -7 always 2 cases one = positive and one = negative
You cannot because 50 is an integer with an absolute value which is greater than 1. It is not a fraction.