|x|=√(x^2).
| 2x + 3 | = 11 make 2 cases case 1) 2x + 3 = 11; solve x = 4 case 2) 2x + 3 = -11; solve x = -7 always 2 cases one = positive and one = negative
I would do it that way.
The expression (a+b) + (a-b) can be rewritten as a + b + a - b = 2a.There is no need to use absolute value.
You cannot because 50 is an integer with an absolute value which is greater than 1. It is not a fraction.
You can write this as two equations, and solve them separately. The two equations are:x - 19 = -3and:-x - 19 = -3
write two numbers that have the given absolute value. 1.4
|x|=√(x^2).
Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.
In order to write f(x) = |x| + |x-2| without the absolute value signs, it it necessary to write it as a piecewise function.We must define f as follows:f(x) = -2x + 2, if x < 0f(x) = 2, if 0
| 2x + 3 | = 11 make 2 cases case 1) 2x + 3 = 11; solve x = 4 case 2) 2x + 3 = -11; solve x = -7 always 2 cases one = positive and one = negative
I would do it that way.
Travis Quaterman
No, because it's absolute value is less than 1.
The expression (a+b) + (a-b) can be rewritten as a + b + a - b = 2a.There is no need to use absolute value.
EX: y=|2x+4| EX: z= -|4s^2|
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