Let's called the first integer x. The second would be x+1 and the third x+2. Adding all these integers together would result in 114:
x+(x+1)+(x+2)=114
x+x+1+x+2=114
3x+3=114
Subtract 3 from both sides:
3x=111
Divide both sides by 3:
x=37
The first number is 37, so the three numbers are 37, 38, and 39.
117
-1, -3, -5
Start with "-3", then add one at a time to get as many consecutive integers as you want.
There are no consecutive odd integers whose sum is equal to 35. 9+11+13 = 33, and 11+13+15 = 39.
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
114/3 = 38, so the three integers are 37, 38 and 39.
117
-1, -3, -5
27, 28, 29
36, 37 and 38.
They are 1986, 1987 and 1988.
129 divided by 3 is 43, so the 3 consecutive integers having a sum of 129 are 42, 43, and 44.
They are: 57+58+59 = 174
The numbers are 121, 122 and 123.
65/67/69
114, 115 & 116
17 + 19 + 21 = 57