Let's called the first integer x. The second would be x+1 and the third x+2. Adding all these integers together would result in 114:
x+(x+1)+(x+2)=114
x+x+1+x+2=114
3x+3=114
Subtract 3 from both sides:
3x=111
Divide both sides by 3:
x=37
The first number is 37, so the three numbers are 37, 38, and 39.
117
-1, -3, -5
There are no consecutive odd integers whose sum is equal to 35. 9+11+13 = 33, and 11+13+15 = 39.
Start with "-3", then add one at a time to get as many consecutive integers as you want.
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
117
-1, -3, -5
There are no consecutive odd integers whose sum is equal to 35. 9+11+13 = 33, and 11+13+15 = 39.
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
201
They are are 62, 63 and 64.
The integers are -6, -5 and -4 OR -7, -5 and -3 using only consecutive odd integers.
-3,-4,-5
The integers are 24, 25 and 26.
Divide the sum of the three consecutive odd integers by 3: 51 / 3 = 17. The smallest of these integers will be two less than 17 and the largest will be two more than 17, so the three consecutive odd integers will be 15, 17, and 19.
Divide the sum of the three consecutive odd integers by 3: 159/3 = 53. The smallest of these integers will be two less than 53 and the largest will be two more than 53, so the three consecutive odd integers will be 51, 53, and 55.
Divide the sum of the three consecutive odd integers by 3: 45/3 = 15. The smallest of these integers will be two less than 15 and the largest will be two more than 15, so the three consecutive odd integers will be 13, 15, and 17.