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x2 - 25 = 0 is x2 = 25 thus x = 5 or x = -5, only 2 real solutions

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How many solutions to a quardratic equation?

A quadratic equation always has TWO (2) solutions. They may be different, the same, or non-existant as real numbers (ie they only exist as complex numbers).


How do you recognize when an equation has no real solution or an infinite number of solutions?

It depends on the equation. Also, the domain must be such that is supports an infinite number of solutions. A quadratic equation, for example, has no real solution if its discriminant is negative. It cannot have an infinite number of solutions. Many trigonometric equations are periodic and consequently have an infinite number of solutions - provided the domain is also infinite. A function defined as follows: f(x) = 1 if x is real f(x) = 0 if x is not real has no real solutions but an infinite number of solutions in complex numbers.


If the discriminant of a quadratic equation is greater than zero which is true A) It has one real solution. B) It has two complex solutions. C) It has two real solutions?

C


How many solutions does a quadratic equation have when it is expressed in the form of ax2 plus bx plus c0 where a does not 0?

Assuming a, b, and c are real numbers, there are three possibilities for the solutions, depending on whether the discriminant - the square root part in the quadratic formula - is positive, zero, or negative:Two real solutionsOne ("double") real solutionTwo complex solutions


Do all linear quadratic systems have two solutions or one?

They will have 2 different solutions or 2 equal solutions and some times none depending on the value of the discriminant within the quadratic equation

Related Questions

You can determine by the discriminant whether the solutions to the equation are or complex numbers?

apex- real


What are the compex roots in mathematics?

The complex roots of an equation is any solution to that equation which cannot be expressed in terms of real numbers. For example, the equation 0 = x² + 5 does not have any solution in real numbers. But in complex numbers, it has solutions.


How many solutions to a quardratic equation?

A quadratic equation always has TWO (2) solutions. They may be different, the same, or non-existant as real numbers (ie they only exist as complex numbers).


If the discriminant of an equation is negative is true of the equation?

If the discriminant of a quadratic equation is negative, it indicates that the equation has no real solutions. Instead, it has two complex conjugate solutions. This occurs because the square root of a negative number is imaginary, leading to solutions that involve imaginary numbers.


If the discriminant of an equation is negative?

It has two complex solutions.


Most quadric equations have?

A quadratic equation can have two real solutions, one real solution, or two complex solutions, none of them real.


How do you recognize when an equation has no real solution or an infinite number of solutions?

It depends on the equation. Also, the domain must be such that is supports an infinite number of solutions. A quadratic equation, for example, has no real solution if its discriminant is negative. It cannot have an infinite number of solutions. Many trigonometric equations are periodic and consequently have an infinite number of solutions - provided the domain is also infinite. A function defined as follows: f(x) = 1 if x is real f(x) = 0 if x is not real has no real solutions but an infinite number of solutions in complex numbers.


You can determine by the discriminant whether the solutions to the equation are real or numbers?

imaginary


If an equation has a degree of three how many solutions will there be?

If the highest degree of an equation is 3, then the equation must have 3 solutions. Solutions can be: 1) 3 real solutions 2) one real and two imaginary solutions.


Is it possible for a cubic equation to have three imaginary solutions?

Yes, a cubic equation can have three imaginary solutions, but this occurs only when all the roots are complex. For a cubic equation with real coefficients, if it has one real root, the other two roots must be complex conjugates, resulting in one real and two imaginary solutions. However, if the cubic has no real roots, it can have three distinct complex roots, all of which would be imaginary.


How many solution will there be if the quadratic equation does not touch or cross the x-axis?

0 real solutions. There are other solutions in the complex planes (with i, the imaginary number), but there are no real solutions.


Why was complex numbers discovered?

They were discovered when Cardano solved the third degree equation. In the formulas that arose to solve the third degree equation, Cardano needed to take the square root of negative numbers and add them up in a certain way. The strange thing that happened was that the formulas used these complex numbers, even if the solutions to the equation where all real. This baffled the mathematicians of the time, because how could these strange numbers turn out to be "real"? Later this was considered totally correct, when the field of complex numbers was better undestood.