1 By factorizing it
2 By sketching it on the Cartesian plane
3 By finding the difference of two squares
4 By completing the square
5 By using the quadratic equation formula
6 By finding its discriminant to see if it has any solutions at all
* Trial and error - only works in the simplest of cases* Factoring - if the polynomial is easy to factor
* Completing the square - this always works, but it's easier if there is no "a" term (for the equation of the form ax^2 + bx + c = 0), and the "b" term is even
* The quadratic equation - this is the most general method, which always works.
The first step is to show an example of the quadratic equation in question because the formula given is only the general form of a quadratic equation.
There are four steps in an algebraic elimination problem. These steps are: to find a variable with equal or opposite coefficients, if equal then subtract the equations but if opposite then add, solve one variable equation left, and then substitute known variable into other equation and solve. hi
That depends on the equation; you need to give some examples of what you want factored. There are four steps to solving an equation. Should any other factors be accounted for when solving an equation? Should any factors be accounted for when explaining how to solve an equation?
each of the four regions created on the coordinate plane by the x- and y-axes.
4/7
Four? Factoring Graphing Quadratic Equation Completing the Square There may be more, but there's at least four.
The 1st step would have been to show a particular quadratic equation in question.
A quadratic equation is an equation that contains four terms and is in standard form ax2 + bx + c = 0. For example, 3x2 + 5x - 2 = 0 Solve by factoring the equation: (3x - 1) (x + 2) = 0 Use the Principal of Zero Products (which says that if the product of two factors is zero, then at least one of those factors is zero) to set each one of those factors to zero. Then solve accordingly. (3x - 1) = 0 (x + 2) = 0 3x = 1 x = -2 x = 1/3 These are the solutions.
The first step is to show an example of the quadratic equation in question because the formula given is only the general form of a quadratic equation.
You can solve a quadratic equation 4 different ways. graphing, which is quick but not reliable, factoring, completing the square and using the quadratic formula. There is a new fifth method, called Diagonal Sum Method, that can quickly and directly give the 2 roots in the form of 2 fractions, without having to factor the equation. It is fast, convenient, and is applicable whenever the equation can be factored. Finally, you can proceed solving in 2 steps any given quadratic equation in standard form. If a=1, solving the equation is much simpler. First, you always solve the equation in standard form by using the Diagonal Sum Method. If it fails to find answer, then you can positively conclude that the equation is not factorable, and consequently, the quadratic formula must be used. In the second step, solve the equation by using the quadratic formula.
The answer is two. Despite its name seems to suggest something to do with four, in a quadratic equation the unknown appears at most to the power of two and so is said to be of second degree. The theorem than pertains here is that the number of roots an equation has is equal to its degrees. However, some of the roots can be repeated - an nth degree equation need not have n different roots. Also the roots do not have to be real. However complex roots ( no real) come in pairs so an equation of odd degree must have at least one real root. A quadratic possibly has no real roots.
Because this equation has four variables, it would require four unique equations involving only these four variables to solve.
True Yes. Although the term 'quad' stands for four, a quadratic equation is a polynomial of second degree.
Yes, it can. For example, if you are solving a quadratic equation, the curve could cross the x-axis in more than one place, thus the equation would have two solutions, a cubic equatuion can have 3 solutions, an equation with a power of four in it can have four solutions, etcetera.
There are four steps in an algebraic elimination problem. These steps are: to find a variable with equal or opposite coefficients, if equal then subtract the equations but if opposite then add, solve one variable equation left, and then substitute known variable into other equation and solve. hi
SRY THE Q IS HOW CAN YOU WRITE AND SOLVE: Twenty four is three less than one-third of a number.?
(4/9) x = That's not an equation. If there were a number after the 'equals' sign, then we could calculate the value of 'x'. But as it is, there's no question there, so there's nothing to solve.