You can solve a quadratic equation 4 different ways. graphing, which is quick but not reliable, factoring, completing the square and using the quadratic formula.
There is a new fifth method, called Diagonal Sum Method, that can quickly and directly give the 2 roots in the form of 2 fractions, without having to factor the equation. It is fast, convenient, and is applicable whenever the equation can be factored. Finally, you can proceed solving in 2 steps any given quadratic equation in standard form. If a=1, solving the equation is much simpler.
First, you always solve the equation in standard form by using the Diagonal Sum Method. If it fails to find answer, then you can positively conclude that the equation is not factorable, and consequently, the quadratic formula must be used.
In the second step, solve the equation by using the quadratic formula.
The four steps to solving equations are.
First it is necessary to simplify the equation by using the distributive property where applicable and combining like terms.
Next, it is necessary to collect all the variables together on one side of the equation by adding or subtracting from each side.
Using inverse operations for addition and subtraction can remove constants next, to get the variables and constants on opposite sides.
Lastly, inverse operations can be used to eliminate coefficients in front of variables to get the variables by themselves. It is important to remember that when multiplying or dividing an inequality by a negative number, the direction of the inequality sign will need to be flipped.
Solving for any variable in an equation differs from equation to equation. You can use various methods such as the quadratic formula, factoring, brute force algebra etc.ExampleSolve x in the the equation logx8=3/2 Answer(5(root(10)))/4
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
(3x+4)(3x-4)=0 x=±4/3
Do you mean -4y2+32y-64 = 0 otherwise it's not an equation because there's no equal sign If so then by using the quadratic equation formula the values of y both equal 4
That depends on the equation.
If the discriminant of a quadratic equation is less then 0 then it will have no real solutions.
(x - 16)(x + 4) = 0 so x = -4 or 16
The discriminant for the quadratic is b2-4ac = 302 - 4*4*45 = 900 - 720 = 180 Since 180 is not a perfect square, the roots of the equation are irrational and it is far from straightforward to solve such an equation by factoring.
-24m = 56Improved answer:First divide all terms by 4 and then solve this quadratic equation by completing the square which will have two solutions:m2-10+14 = 0(m-5)2+14 = 0(m-5)2+14-25 = 0(m-5)2 = 11m-5 = + or - the square root of 11m = 5 + or 5 - the square root of 11Alternatively you can solve this equation by using the quadratic equation formula which will give you the same answer.Your tutor should be familiar with the above methods of solving quadratic equations if you aren't too sure.
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You want to create an equation for this. The equation should look like this: x^2 - 2x + 4 = 0 Use the quadratic equation to solve it.