I do not understand the question because there are 18 pairs of palidromic numbers that sum to 585.
39
Given the expression 36y + 9 If y = 16, then 36*16 + 9 = 576 + 9 = 585
The prime factors are 2x2x2x13 All factors are 1,104,2,52,4,26,8,13
the answer is ........ factors are 1,2,3,6,9,18 ; 1x18,2x9,3x6 prime factors are 2x3x3
The prime factors of 585 are: 3, 5 and 13The prime numbers (factors) of 585 are: 3,5,13
The factors of 585 are: 1 3 5 9 13 15 39 45 65 117 195 585 The prime factors are: 3 5 13
As a product of its prime factors: 3*3*5*13 = 585 or as 32*5*13 = 585
The prime factors of 585 are: 3 5 13:3 x 5 x 13 =195
Factors of 585: 1, 3, 5, 9, 13, 15, 39, 45, 65, 117, 195, 585.Factors of 180: 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180.GCF (585, 180) = 45
To determine what numbers 585 is divisible by, we need to find its factors. 585 is divisible by 1, 3, 5, 9, 13, 15, 39, 45, 65, 117, 195, and 585 itself. This means that 585 can be divided evenly by any of these numbers without leaving a remainder.
The factors of 1,755 are: 1, 3, 5, 9, 13, 15, 27, 39, 45, 65, 117, 135, 195, 351, 585, 1755.
The factors of 1755 are: 1 3 5 9 13 15 27 39 45 65 117 135 195 351 585 1755
585/2 = 292.5
585
No: 585 divided by 6 is 97 with remainder 3.
Yes, 585 divided by 9 is 65