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Two numbers that when added equal 56 and when multiplied equal 783?
X + Y = 56 [therefore] X = 56 - Y XY = 783 [therefore] (56 - Y)(Y) = 783 56Y - Y^2 = 783 solve for Y, then don't forget to plug Y back into the original and find "X" (X = 56 - Y ) a+b = 56 AND: ab = 783 substitution: a = 56-b (from addition equation) put this back into the multiplication equation: (56-b)b = 783 expansion: 56b -b^2 = 783 rearrange: -b^2 + 56b - 783 quadratic formula: b = (-56+sqrt(3136-4(-1)(-783))) / -2 and b = (-56-sqrt(3136-4(-1)(-783))) / -2 b=27 and b=29 from the addition equation: 56-27 = a=29 56-29 = a =27 it's kind of a "repeat" question
The product of two consecutive odd integers is 783?
Oh, isn't that just a happy little math problem? Let's think about it together. If we have two consecutive odd integers, we can call them n and n+2. When we multiply them together, we get n(n+2) = 783. By solving this equation gently, we find that the two numbers are 27 and 29.
What are the factors and prime factors of 104?
The prime factors are 2x2x2x13 All factors are 1,104,2,52,4,26,8,13
What are the factors and prime factors of18?
the answer is ........ factors are 1,2,3,6,9,18 ; 1x18,2x9,3x6 prime factors are 2x3x3
How many factors does 100?
1,2,4,5,10,20,25,50,100 9 factors in total.
