9, 17, 25, 33, 41
The nth term is Un = a + (n-1)*d where a = U1 is the first term, and d is the common difference.
All the terms are the same. If Y is the amount and r the percentage then the nth term is Y*r/100 for all n.
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
123456789 * * * * * The nth term is 3n
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
5 first terms in n²+3
no clue
nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
2,1,0 is th sequence of its terms
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
14112027
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
The first four terms are 3 9 27 81 and 729 is the 6th term.
Yes. You can have as many nth terms as you can be bothered to write down!
5, 11, 17, 23, 29
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.