t(1)= = 9*1 - 3 = 9 - 3 = 6
t(2)= = 9*2 - 3 = 18 - 3 = 15
t(3)= = 9*3 - 3 = 27 - 3 = 24
t(4)= = 9*4 - 3 = 36 - 3 = 33
t(5)= = 9*5 - 3 = 45 - 3 = 42
9, 17, 25, 33, 41
The nth term is Un = a + (n-1)*d where a = U1 is the first term, and d is the common difference.
All the terms are the same. If Y is the amount and r the percentage then the nth term is Y*r/100 for all n.
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
First look for the difference between the terms, for example the sequence: 5, 8, 11, 14... has a difference of 3. This means the sequence follows the 3 times table - i.e. 3n Now since we need the first term to be 5 we add 2 to our rule to make it work. So the nth term of this sequence is 3n + 2.
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
5 first terms in n²+3
no clue
nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
2,1,0 is th sequence of its terms
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
14112027
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
To find the nth term of the linear sequence -9, -5, -1, we first identify the common difference between the terms. The difference between consecutive terms is 4. The first term (a) is -9, so the nth term can be expressed as ( a_n = -9 + (n-1) \cdot 4 ), which simplifies to ( a_n = 4n - 13 ).
The first four terms are 3 9 27 81 and 729 is the 6th term.
Yes. You can have as many nth terms as you can be bothered to write down!
To find the nth term of the sequence 3, 11, 25, 45, we first look for a pattern in the differences between the terms. The first differences are 8, 14, and 20, and the second differences are 6, 6, indicating that the sequence is quadratic. We can express the nth term as ( a_n = An^2 + Bn + C ). Solving for A, B, and C using the given terms, we find the nth term is ( a_n = 3n^2 - 3n + 3 ).