If the nth term is n*7 then the first 5 terms are
7, 14, 21, 28, 35.
you must find the pattern of the sequence in order to find the next 50 terms using that pattern and the first part of the sequence given
The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
4,8,12,16,20
14112027
6
5
you must find the pattern of the sequence in order to find the next 50 terms using that pattern and the first part of the sequence given
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
2,1,0 is th sequence of its terms
The first four terms are 3 9 27 81 and 729 is the 6th term.
4,8,12,16,20
The general (or nth) term is given by the equation t(n) = a + (n-1)d where a is the first term and d is the common difference between successive terms.
Given that the second differences of the sequence are a constant 2, the sequence can be modeled as a quadratic function. The general form of a quadratic sequence is ( an^2 + bn + c ). With the fourth term being 27 and the fifth term being 39, we can set up equations to find the coefficients. Solving these, we find that the first three terms of the sequence are 15, 21, and 27.
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
14112027
The nth term of the sequence given by the formula (2 - n) can be found by substituting (n) with the first three positive integers: For (n = 1): (2 - 1 = 1) For (n = 2): (2 - 2 = 0) For (n = 3): (2 - 3 = -1) Thus, the first three terms of the sequence are 1, 0, and -1.