The last digit in the product of the first 20 odd natural numbers can be determined by looking at the pattern of the units digit in the multiplication of consecutive odd numbers. The units digit of the product of consecutive odd numbers alternates between 1 and 5. Since there are 10 odd numbers between 1 and 19, and 20 is also an odd number, the last digit in the product of the first 20 odd natural numbers is 5.
36
Yes. Basic rule is two odds make an even, two evens make an even, an even and an odd make an odd. And note that any two consecutive numbers include exactly one odd and one even. Or more directly, if you start at number n you will add it to n+1 giving 2n+1. Since 2n is even, 2n+1 is odd.
55 is an odd number. Odd numbers end in 1, 3, 5, 7, or 9. Even numbers end in 0, 2, 4, 6, or 8.
over 50
201
201
200*50=10000
The sum of all odd numbers 1 through 99 is 9,801.
200
The sum of all the numbers 1 through 200 is 20,100.
To determine the number of odd numbers between 100 and 200, we need to consider that odd numbers are integers that are not divisible by 2. The first odd number in this range is 101, and the last odd number is 199. To find the total count, we can subtract the first odd number from the last odd number and divide by 2, then add 1 to include both endpoints. So, (199 - 101) / 2 + 1 = 50 odd numbers.
The sum of all the odd numbers from 1 through 100 is 10,000
First odd number greater than 20 is 21 Last odd number less than 200 is 199 → number of odd numbers between 20 and 200 is (199 - 21) ÷ 2 + 1 = 90
100
201
There are 100 odd numbers between 1 and 199. This can be calculated by dividing the total range (199 - 1 = 198) by 2, as odd numbers are spaced every two integers. Therefore, 198 divided by 2 equals 99, representing half of the odd numbers in the range. Multiplying this by 2 gives us the total count of odd numbers, which is 100.