1 - x3 = (1 - x)(1 + x + x2) So the roots are 1 (the root of 1 - x) and [-1 +/- sqrt(-3)]/2 (the roots of x2 + x + 1, via the quadratic formula. Note: Sqrt means "square root", and +/- means "plus-or-minus". This site has no easy access to those symbols.
(x - 1)(x^2 + x + 1)
x^3-x = x(x^2-1) = x(x+1)(x-1)
Factor out the GCF and get X(X2-X+1).
The roots of 1 - x3 are 1 - x and 1 + x + x2, by application of the difference-of-cubes formula.
24
(x - 1)(x - 1)(x - 1) - (x + 1)(x + 1)(x + 1)
Only one (minus 5).
xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1
X cubed - X cubed is zero.
x(x + 1)(x -1)
(x - 1)(x^2 + x + 1)
(x - 1)(x^2 + x + 1)
I am assuming you need this factored. x(x+1)(x-1)
2x(x−6)(x+1)
(x - 5)(x^2 + 1)
x³ - x² + x - 3 (x² + 1)(x - 1) - 2
t3-1/27