64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
(x - 1)(x - 1)(x - 1) - (x + 1)(x + 1)(x + 1)
x(x + 3)(x - 4)
The answer is -x3 + x
x cubed minus 216
24
2x(x−6)(x+1)
(x - 2)(x^2 + x + 3)
(x - 5)(x^2 + 1)
2(5x - 6y)(25x2 + 30xy + 36y2)
x(x + 1)(x -1)
xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1