1+x2 is a polynomial and doesn't have a real root.
No,
No itβs not a factor
5
true
A "root" of a polynomial is any value which, when replaced for the variable, results in the polynomial evaluating to zero. For example, in the polynomial x2 - 9, if you replace "x" by 3, or by -3, the resulting expression is equal to zero.
A root or a zero of the polynomial.
A root.
1+x2 is a polynomial and doesn't have a real root.
π is a transcendental number which is defined to be the ratio between the diameter and circumference of any circle. (A transcendental number is a number which is not a root of a non-zero polynomial with rational coefficients.)
If you mean a math problem, "root" is another word for "solution".The "root" of a polynomial in "x" is any value for "x" which will set the polynomial equal to zero, when evaluated.If you mean a math problem, "root" is another word for "solution".The "root" of a polynomial in "x" is any value for "x" which will set the polynomial equal to zero, when evaluated.If you mean a math problem, "root" is another word for "solution".The "root" of a polynomial in "x" is any value for "x" which will set the polynomial equal to zero, when evaluated.If you mean a math problem, "root" is another word for "solution".The "root" of a polynomial in "x" is any value for "x" which will set the polynomial equal to zero, when evaluated.
Yes, it is a linear polynomial.
No,
It is a polynomial if the square root is in a coefficient but not if it is applied to the variable. A polynomial can have only integer powers of the variable. Thus: sqrt(2)*x3 + 4*x + 3 is a polynomial expression but 2*x3 + 4*sqrt(x) + 3 is not.
A value of the variable that makes the polynomial equal to zero (apex)
No itβs not a factor
No. by definition, the polynomial should contain an integer as exponent and square root 1/2 is not an integer.