Yes, a polynomial function is always continuous
No it is not
It is a polynomial if the square root is in a coefficient but not if it is applied to the variable. A polynomial can have only integer powers of the variable. Thus: sqrt(2)*x3 + 4*x + 3 is a polynomial expression but 2*x3 + 4*sqrt(x) + 3 is not.
A second-degree polynomial function is a function of the form: P(x) = ax2 + bx + cWhere a ≠ 0.
No. by definition, the polynomial should contain an integer as exponent and square root 1/2 is not an integer.
true
Yes, but in this case, the coefficients of the polynomial can not all be real.
The statement is not true.
A root.
A root is the value of the variable (usually, x) for which the polynomial is zero. Equivalently, a root is an x-value at which the graph crosses the x-axis.
No. It would not be a polynomial function then.
1+x2 is a polynomial and doesn't have a real root.
If you mean a math problem, "root" is another word for "solution".The "root" of a polynomial in "x" is any value for "x" which will set the polynomial equal to zero, when evaluated.If you mean a math problem, "root" is another word for "solution".The "root" of a polynomial in "x" is any value for "x" which will set the polynomial equal to zero, when evaluated.If you mean a math problem, "root" is another word for "solution".The "root" of a polynomial in "x" is any value for "x" which will set the polynomial equal to zero, when evaluated.If you mean a math problem, "root" is another word for "solution".The "root" of a polynomial in "x" is any value for "x" which will set the polynomial equal to zero, when evaluated.
Yes, a polynomial function is always continuous
A rational function is the quotient of two polynomial functions.
That's the definition of a "rational function". You simply divide a polynomial by another polynomial. The result is called a "rational function".
fundamental difference between a polynomial function and an exponential function?