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Ah, an EQ of 126 is a wonderful thing to explore! It means you have a high level of emotional intelligence, which allows you to understand and manage your own emotions, as well as empathize with others. It's like having a palette full of colors to navigate the beautiful landscape of human relationships. Keep nurturing your emotional intelligence, and watch how it enriches your life and those around you.

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BobBot

5mo ago

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Solve the simultaneous equations 4x plus 3y equals -5 3x plus 5y equals -12?

4x + 3y = -5 (Eq 1); 3x + 5y = -12 (Eq 2) Eliminate x Eq 1 times 3: 12x + 9y = -15 Eq 2 times 4: 12x +20y = -48 Subtract Eq 1 from Eq 2 11y = -48-(-15) ie 11y = -33 y = -3 Substitute in Eq 1: 4x - 9 = -5, ie 4x = 4 so x = 1 Check in Eq 2: (3 x 1) + (5 x -3) = 3 - 15 = -12. QED


How do IQ and eq differ?

IQ is intelligence quotient. EQ is emotional intelligence. They measure different things. IQ is essentially the same through your life. EQ can go up as you grow wiser and better at dealing with people.


X plus 7y equals 39 and 3x minus 2y equals 2?

x + 7y = 39 ....... Eq.13x - 2y = 2 ....... Eq.2multiply Eq.1 with (-3) and so Eq.1 will be :-3x - 21y = -1173x - 2y = 2_________________ by Elimination method ( Eq.1 + Eq.2 ) the result will we :- 21y - 2y = - 115-23y = -115Y = 5to find the value of x, put the value of y in Eq.1 :x + 7y = 39x = 39 - 7yx = 39 - 7(5)X = 4___________________________________________________________you can solve it in another way by using substitution method:x + 7y = 39 ....... Eq.1 ,, you can write it in another form, x = 39 - 7y3x - 2y = 2 ....... Eq.2Put the value of Eq.1 on Eq.23(39 - 7y) - 2y = 2117 - 21y - 2y = 2117 - 23y = 223y = 115 ............ Y = 5to find the value of X , put the value of Y in Eq.1x = 39 - 7yx = 39 - 7(5)x = 39 - 35 .............. X = 4and so in both ways....you got the same answer choose the easiest way for you :)good luck my friend...


What is the absolute value of 126?

-60


How do you find exponent N in 126 n12?

126 = n^12 12 = log(base n)126 Since log(base n)(126) = log 126/log n or log(base n)(126) = ln 126/ln n we write: 12 = ln 126/ln n 12 ln n = ln 126 ln n = ln 126/12 ln n = 0.4030234922 rewrite the natural logarithm showing base e (optional) log(base e)(n)= 0.4030234922 e^0.4030234922 = n Check e^0.4030234922 126 = (e^0.4030234922)^12 ? 126 = e^4.836281907 ? 126 = 126 True