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126 = n^12

12 = log(base n)126

Since log(base n)(126) = log 126/log n or log(base n)(126) = ln 126/ln n we write:

12 = ln 126/ln n

12 ln n = ln 126

ln n = ln 126/12

ln n = 0.4030234922 rewrite the natural logarithm showing base e (optional)

log(base e)(n)= 0.4030234922

e^0.4030234922 = n

Check e^0.4030234922

126 = (e^0.4030234922)^12 ?

126 = e^4.836281907 ?

126 = 126 True

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Q: How do you find exponent N in 126 n12?
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