v equals m divided by p
To prove a ring is commutative, one must show that for any two elements of the ring their product does not depend on the order in which you multiply them. For example, if p and q are any two elements of your ring then p*q must equal q*p in order for the ring to be commutative. Note that not every ring is commutative, in some rings p*q does not equal q*p for arbitrary q and p (for example, the ring of 2x2 matrices).
The difference of p and q can be written : p - q Twice the difference is therefore 2 x (p - q) which can also be written as 2(p - q) OR 2p - 2q. Consequently you can create another variable (say) y and make this equal to twice the difference of p and q by simply writing, y = 2(p -q)
0.142678
P squared = P*P. When divided by P, the equation becomes (P*P/P, and the answer is "P".
13p/13p = Cacek diwb by 'p' HYence 13/13 = Cancel down by '13' Hence =1. The answer !!!!
The fraction 13p/1 pound = 13 p/100 p = 13/100.This fraction cannot be simplified.
p=10
P2 + 13p - 30 = 0 Answer: p= -15, p = 2
p = -12
This can be simplified to -10p = -150 p = -150/-10 p = 15
The solution isp = +2 or p = -15 .Here is how to get it.p2 + 13p - 30 = (p - 2) ((p + 15)So, if p2 + 13p - 30 = 0 then (p - 2) ((p + 15) = 0.The product of two numbers equals 0 if and only one of the factors is zero.so solve the linear equations:p -2 = 0 and p + 15 = 0 and getp = +2 or p = -15 .
It is 13p/1
1
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution. The most that you can do is: 13p = 31-7k so that p = (31-7k)/13
-31=8-6p-7p -31=8-13p ==add the -6p and the - 7p together -39=13p =======move the 8 over to the other side p=3 =======divide both sides by 13 to get p by itself
13 + 16 = 29 40 - 29 = 11 therefore 11 is require to make 40p