pi2r can be calculated, but is has no particular mathematical interpretation.
Chat with our AI personalities
A = pi r2r2 = A/pir2(1/2) = (A/pi)1/2r = (120/pi)1/2r ≈ 6 inC = 2 pi rC = (2)(pi)(6 in)C ≈ 37.7 in
C = 2*pi*r 8 = 2*pi*r 4 = pi*r r = 4/pi
Remember the circle equations. A = pi r^2 C = 2 pi r = pi d ( Hence d = 2r) Algebraically rarranging r = sqrt(A/pi) 2r = d = 2(sqrt(A/pi)) Hence d = 2(sqrt(28.26 / 3.141592...)) d = 2(sqrt(8.99543....) d = 2(2.999239...) d = 5.99847.... ~ 6 The answer!!!!!
V = (pi)*R2*H if you double the radius then put 2R in place of R in the formula: V = (pi)*(2R)2*H V = 4pi*R2*H So the volume will increase 4 fold if you double the cylinder's radius.
circumference equal two times 'pi' times radius. It is written algebraically as C = 2pir Since 2r = d (diameter) Then C = pi*d Also the area (A) of a circle is A = pi*r^(2) 'pi' is the constant of proportion of circles. NB For school work pi = 3.14 or pi = 3.1416 or pi = 22/7