point-slope form looks like... y-y1=m(x-x1) these parts stay the same.... y- = (x- ) and you plug in the ordere4d pair you are given into it. So if the ordered pair is (2,3) (x,y) it will be y-3=m(x-2)
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y - y1 = m(x - x1), where m is the slope of the line, and (x1, y1) is a point on the line.
The equation of a line can be written in a format called "point slope form". Equations in this form look like y - y1= m(x - x1). In this formula (x1,y1) is any point on the line, m is the slope, x is the input (or dependent variable) and y is the output or dependent variable. Using this, and a given slope and point, you can construct the equation for a line. The y-intercept is the point where a line crosses the y-axis. You don't know where on the y-axis, but you know that the x-value of any point of the y-axis is 0. Therefore, you can solve for the y-intercept bus substituting 0 for x and solving for y.
For every unit a point travels in the positive x direction, it travels 2.51 units in the positive y direction.
Assuming 6 is the x-coordinate and 5 is the y-coordinate, you plot your first point at (6,5). From the (0,0) point, you go to the right 6 units, and then up 5 units. Put a dot there. A line with a 0 slope is a horizontal line, so you just draw that line through the point (6,5). The line would look the same regardless of what x value is named in your equation. The equation would read y=5, because the x-coordinate is not used in slope-intercept form (y=mx+b).
Two lines with the same slope and y-intercept look like one single line. The "system" of equations consists of the same equation twice. The lines coincide at every point, which means there are an infinite number of solutions.