y - y1 = m(x - x1), where m is the slope of the line, and (x1, y1) is a point on the line.
you look at the line and see if there are any direct points on the line the slope formula
The equation of a line can be written in a format called "point slope form". Equations in this form look like y - y1= m(x - x1). In this formula (x1,y1) is any point on the line, m is the slope, x is the input (or dependent variable) and y is the output or dependent variable. Using this, and a given slope and point, you can construct the equation for a line. The y-intercept is the point where a line crosses the y-axis. You don't know where on the y-axis, but you know that the x-value of any point of the y-axis is 0. Therefore, you can solve for the y-intercept bus substituting 0 for x and solving for y.
For every unit a point travels in the positive x direction, it travels 2.51 units in the positive y direction.
point-slope form looks like... y-y1=m(x-x1) these parts stay the same.... y- = (x- ) and you plug in the ordere4d pair you are given into it. So if the ordered pair is (2,3) (x,y) it will be y-3=m(x-2)
Two lines with the same slope and y-intercept look like one single line. The "system" of equations consists of the same equation twice. The lines coincide at every point, which means there are an infinite number of solutions.
Undefined slope is a vertical line along the horizontal point of origin., the slope would have a denominator of zero, which is undefined.
When it is a line through the origin.
you look at the line and see if there are any direct points on the line the slope formula
you look at the line and see if there are any direct points on the line the slope formula
y - y1 = m (x - x1) If your point was (5,4) and your slope was 3, then the equation would look like this: y - 4 = 3 (x - 5) Then you would use distributive property to solve from there...but continueing to solve would not be point-slope form... y-4=3(x-5) would be your complete answer for a question asking to write an equation in point-slope form.
The equation of a line can be written in a format called "point slope form". Equations in this form look like y - y1= m(x - x1). In this formula (x1,y1) is any point on the line, m is the slope, x is the input (or dependent variable) and y is the output or dependent variable. Using this, and a given slope and point, you can construct the equation for a line. The y-intercept is the point where a line crosses the y-axis. You don't know where on the y-axis, but you know that the x-value of any point of the y-axis is 0. Therefore, you can solve for the y-intercept bus substituting 0 for x and solving for y.
For every unit a point travels in the positive x direction, it travels 2.51 units in the positive y direction.
point-slope form looks like... y-y1=m(x-x1) these parts stay the same.... y- = (x- ) and you plug in the ordere4d pair you are given into it. So if the ordered pair is (2,3) (x,y) it will be y-3=m(x-2)
a horizontal line
The standard form of the slope-intercept equation is: y = mx + b where "m" is the slope, and "b" is the y-intercept.
True ~APEX
If you look at the slope intercept formula (y=mx+b), and the m is positive, then the line will have an upward slope (ex. y=8x+2) if the m is negative the line will have a downward slope (ex. y=-9x+6).