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What else can I help you with?
How do you use absolute value to find the distance between two points that have the same x coordinates but?
It is simply the difference between their y coordinates.
How do you work out diagonal of a square?
It is the longest distance between two opposite corners of the square and it is possible to use Pythagoras' theorem to find the length of the diagonal
What do you use to find the value of an algebraic expression?
You replace variables by their assigned values, then do the calculations.
What is expression can be use to find THE APPROXImate circumference of a outer circle?
Radius * 2 * pi (you might aswell use the computer's calculator in scientific mode)
Find the distance between the points -10 8 and -2 -7?
Use Pythagoras' Theorem: calculate the square root of ((difference of x-coordinates)2 + (difference of y-coordinates)2).
How can you find the expression can you use to find the distance between 28 and -53?
To find the distance between two numbers, you can use the formula ( \text{Distance} = |a - b| ), where ( a ) and ( b ) are the two numbers. In this case, you would calculate ( |28 - (-53)| ) or ( |28 + 53| ). This simplifies to ( |28 + 53| = |81| = 81 ). Thus, the distance between 28 and -53 is 81.
How do you find the distance on a coordinate map?
To find the distance on a coordinate map, you can use the Pythagorean theorem to calculate the shortest distance between two points. Simply calculate the horizontal and vertical differences between the points, then use these differences as the sides of a right triangle to find the distance.
To find the distance between two points in the plane you can always use the distance formula?
True
To find the distance between any two points in the plane you can always use the Distance Formula?
True
To find the distance between any two points in the plane you can always use the distance formula.?
True
How do you find distance between two points in geometry?
If you know the end points then use the distance formula or simply use a ruler.
What expression gives the distance between the points 51 and 9-6?
To find the distance between the points 51 and 9-6, we first need to determine the coordinates. Assuming the first point is (51, 0) and the second point is (9, -6), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting in the values, the expression becomes: [ d = \sqrt{(9 - 51)^2 + (-6 - 0)^2} ]
What would you use to find the distance between two places on a map?
the scale
How do you find the distance between the two furthest corners of a square?
Use a ruler.
Explain how to find the distance between the points (28 -17) and (-15-17) on a coordinate plane?
To find the distance between any two points on the Cartesian plane use Pythagoras: The distance between (x0, y0) and (x1, y1) is given by: distance = √((x1 - x0)² + (y1 - y0)²) → distance between (28, -17) and (-15, -17) is: distance = √((x1 - x0)² + (y1 - y0)²) = √((-15 - 28)² + (-17 - -17)²) = √((-43)² + (0)) = √1849 = 43 ------------------------ In this case, the y-coordinates are the same (y0 = y1 = -17), so this becomes: distance = √((x1 - x0)² + (y0 - y0)²) = √((x1 - x0)² + 0²) = √((x1 - x0)²) = |x1 - x0| The vertical bars around the expression mean the absolute value of the expression, which is the numerical value of the expression ignoring the sign. distance = |x1 - x0| = |-15 - 28| = |-43| = 43.
Which expression gives you the distance between the points (2 5) and -4 8)?
To find the distance between the points (2, 5) and (-4, 8), you can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Plugging in the coordinates, the expression becomes: [ d = \sqrt{((-4) - 2)^2 + (8 - 5)^2} = \sqrt{(-6)^2 + (3)^2} = \sqrt{36 + 9} = \sqrt{45} ] Thus, the distance is ( \sqrt{45} ) or ( 3\sqrt{5} ).
Which expression gives the distance between the points (25) and (-4 8)?
To find the distance between the points (2, 5) and (-4, 8), you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Substituting the coordinates, the expression becomes ( d = \sqrt{((-4) - 2)^2 + (8 - 5)^2} ), which simplifies to ( d = \sqrt{(-6)^2 + (3)^2} = \sqrt{36 + 9} = \sqrt{45} ). Thus, the distance is ( \sqrt{45} ) or ( 3\sqrt{5} ).
