There are infinitely many possible answer.
Pick any 4 numbers, a, b, c and d. And then let the fifth number, e = 300 - (a + b + c+ d)
Then a, b, c, d and e have an average of 300. Since the choice of a, b c and d was arbitrary, there are infinitely many possible answer.
For example, today's date is 22 November 2012 and the local time now is 1123
So let the first four number be 22 , 11 , 12 and 1123
Then the fifth is 300 - (22 + 11 + 12 + 1123) = -868
The average of the 5 numbers is 1/5*(22 + 11 +12 + 1123 -868) = 1/5*300 = 60
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Yes. If the predominant data are higher than the median, the mean average will be higher than the median average. For example, the median average of the numbers one through ten is five. The mean average is five and one-half.
61
The numbers are 10 and 5
60 x 40 = 2400 40 x 60 = 2400 4800 / 100 = 48
30 and 60, among others.