Absolutely nothing. A scale factor of 1 is the same as saying do not change the scale.
With a scale factor of 1, the image is exactly the same size as the original object.
There are four forms of linear transformation on the Cartesian plane which is used in engineering and they are:- Translation moves a shape in the same direction and distance Refection is a 'mirror image' of a shape Enlargement changes the size of a shape by a scale factor Rotation turns a shape through an angle at a fixed point
Image over preimage(original)
Assuming the smaller sphere is the image of the larger sphere after transformation (based on the order of the radii): the scale factor is 4/12 = 1/3
If you are dilating the image about some factor, you can multiply coordinates by the constant. For instance... ½(1,2) = (½,½ * 2) = (½, 1)
It depends on the aspect ratio. If it is a square object then it should scale up evenly. But if it is a rectangle then eventually a large enough scale factor will make it looked stretch on the longer sides.
A negative scale factor is used to produce the image on the other side of the centre of enlargement (scaled to the absolute value of the scale factor).
with your image resolution? Nothing happens it remains the same till you change it in Image Size dialog. Image > Image Size.. Magnification is for your convenience to see enlarged image nothing really happens to actual resolution of original image.
The image is upright and magnified/enlarged.
The lenses of a microscope form an enlarged image of a specimen.
The image is bigger than the pre-image.
It is an enlargement
When enlarging a shape through a centre (O in this case, which is the usual letter of the origin for x/y axes) measure the distance from each point on the shape to the centre of enlargement, multiply it by the scale factor to get the new distance and then (keeping the measuring device, eg ruler, still) measure the new distance from the centre.By having a scale factor the exact size of the image is known; andby having a centre of enlargement the exact position of the image is known.Note: When the scale factor is negative, the distances will change sign and so be measured in the opposite direction.So in this case, the following will happen:. . . . . . . . . . . . . . . . . . . . . .. . . ./\ . . . . . . . . . . . . . . . . .. . . / .\. . . . . . . . . . . . . . . . .. . ./__\ . . . . . .O . . . \ . . ./. .. . / . . .\. . . . . . .* . . . \--/. .. ./. . . . \ . . . . . . . . . . .\/ . . .. / . . . . .\. . . . . . . . . . . . . . .. . . . . . . . . . . . . . . . . . . . . .Where the A shape on the left becomes the (smaller) upside down A on the right when enlarged with a scale factor of -½ and centre O.(You'll have to excuse the ASCII graphics for not complete accuracy.)
Convex lens gives an enlarged image when the object is placed between F and 2F, at F and between F and C.
an enlarged, upside-down virual image.
microscope
An enlargement is usually described by a scale factor, f, AND a centre of enlargement, O. For simplicity, I will refer to the original shape or the pre-image as A, and the image, after enlargement, as B.Take any point P, on A. Join OP. Multiply the distance OP by f. Extend the line OP to OQ so that its length is which OP*f. Then Q is the image of P. In principle, you need to repeat this for every point on the shape A. However, if A is a shape made up of straight lines (a polygon in 2d or polyhedron on 3d) , you need only find the images of its vertices and join them up with straight lines in the same order. Unfortunately, this does not work with curved shapes.In mathematical terms, "enlargement" can also mean shrinking. If the scale factor f is between 0 and 1, the image will be smaller than the pre-image.Also, if f is negative, then the image will be an inverted image on the other side of O. Again, the image will be smaller than the pre-image if the absolute value of f is less than 1 (ie -1< f