The interior angles add up to 3600 degrees
Oh, dude, a 22-sided polygon? That's like a party with 22 corners! So, a polygon has the same number of vertices as its number of sides, so there are 22 vertices in a 22-sided polygon. It's like math, but with shapes and stuff.
(22-2)180 (20)180 = 3,600
Total of interior angles is 22 - 4 right angles so hendecagon angles would be 18 x 90/11 ie 147.27 degrees.
The sum of interior angles of any triangle is 180 degrees. A right triangle is defined as a triangle having one angle that measures 90 degrees. Therefore, it follows that the sum of the remaining two angles will be 90 degrees 90-68=22 The third angle is 22 degrees
The formula for finding the interior angle of any shape is: [180*(n-2)]/n, with n being the number of sides you have.In your case, you have a 24-gon. Plug it in for your n, and you have[180*(24-2)]/24 -> [180*22]/24 -> 3960/24 -> 165So the interior angle would be 165o.
22 sides
The sum of the interior angles of a polygon can be calculated using the formula ( (n - 2) \times 180^\circ ), where ( n ) is the number of sides. For a polygon with 22 sides, the sum of the interior angles is ( (22 - 2) \times 180^\circ = 20 \times 180^\circ = 3600^\circ ). Each interior angle of a regular 22-sided polygon would therefore be ( \frac{3600^\circ}{22} \approx 163.64^\circ ).
If the interior angles add up to 3600 degrees then it will have 22 sides
The formula is: (n-2)*180 = sum of interior angles whereas 'n' is the number of sides of the polygon.
There is a formula you can use to determine the sum of the interior angles of any polygon with n number of sides:(n-2) * 180oso in your case it would be (22-2)*180o = 3600o
22/3 sides.-- The smallest possible number of sides for a polygon is 3, in a triangle.If the triangle is regular, then each interior angle is 60 degrees.-- The next polygon is the quadrilateral, with 4 sides. If the quadrilateralis regular, then each interior angle is 90 degrees.-- We can see that as the number of sides increases, the interior angles get bigger.-- So the triangle is the polygon with the smallest interior angles.And those are 60 degrees, so a polygon with all45-degree interior anglesisn't possible. Some of them could be, but never all.
To find the sum of the interior angles of a polygon, you can use the formula ( (n - 2) \times 180 ), where ( n ) is the number of sides. For a 22-sided polygon, the calculation is ( (22 - 2) \times 180 = 20 \times 180 = 3600 ) degrees. Therefore, the sum of the interior angles in a 22-sided polygon is 3600 degrees.
20 sides. The interior angles of a polygon add up to 180(n-2). We solve: 180(n-2) = 3960 n-2 = 22 n-2(+2) = 22(+2) n=24
(22-2)*180=3600
If the sum of its interior angles is 22*90 which is 1980 degrees then it will have 13 sides Consider the following rules that are applicable to all polygons:- (interior angles+360) divided by 180 = number of sides (number of sides -2) multiplied by 180 = sum of interior angles The above question is rather confusing because it implies that the interior angles of the polygon is the equivalent of twenty two right angles which is the same as 1980 degrees but working out how many sides the polygon has then the same rules apply. (1980+360)/180 = 13 sides (13 -2)*180 = 1980 degrees
The sum of the interior angles of a 22-sided polygon (icosikaitriangle) can be calculated using the formula ((n - 2) \times 180) degrees, where (n) is the number of sides. For a 22-sided figure, the sum of the interior angles is ((22 - 2) \times 180 = 20 \times 180 = 3600) degrees. Therefore, the sum of the interior angles of a 22-sided polygon is 3600 degrees.
Suppose the polygon has n sides Then sum of interior angles = (n-2)*180 degrees = 3960 degrees so n-2 = 3960/180 = 22 and so n = 24