20 sides. The interior angles of a polygon add up to 180(n-2). We solve: 180(n-2) = 3960 n-2 = 22 n-2(+2) = 22(+2) n=24
To find the measure of each interior angle in a polygon when the sum of the angles is given, you divide the total sum by the number of angles in the polygon. If the sum of the interior angles is 3960, and the polygon is a hexagon (6 sides), each interior angle would measure 660 degrees (3960 ÷ 6 = 660). This is because the sum of the interior angles of a polygon with n sides is given by (n-2) * 180 degrees.
163.6363... degrees.
Exterior angles add up to 360 degrees Interior angles add up to 3600 degrees
If you look at the polygons we see from day to day, you can see that the sum of their interior angles follows a pattern:number of sides: sum of angles3: 1804: 3605: 5406: 720..In other words, its 180(n - 2), where n is the number of sides on the polygon.So to work out how many sides that polygon has, you can say:1980 = 180(n - 2)∴ n - 2 = 1980/180∴ n = 22 - 2∴ n = 20So this polygon is a twenty-sided one, or an "icosagon".
The interior angles add up to 3600 degrees
22 sides
If the interior angles add up to 3600 degrees then it will have 22 sides
The formula is: (n-2)*180 = sum of interior angles whereas 'n' is the number of sides of the polygon.
There is a formula you can use to determine the sum of the interior angles of any polygon with n number of sides:(n-2) * 180oso in your case it would be (22-2)*180o = 3600o
22/3 sides.-- The smallest possible number of sides for a polygon is 3, in a triangle.If the triangle is regular, then each interior angle is 60 degrees.-- The next polygon is the quadrilateral, with 4 sides. If the quadrilateralis regular, then each interior angle is 90 degrees.-- We can see that as the number of sides increases, the interior angles get bigger.-- So the triangle is the polygon with the smallest interior angles.And those are 60 degrees, so a polygon with all45-degree interior anglesisn't possible. Some of them could be, but never all.
20 sides. The interior angles of a polygon add up to 180(n-2). We solve: 180(n-2) = 3960 n-2 = 22 n-2(+2) = 22(+2) n=24
(22-2)*180=3600
If the sum of its interior angles is 22*90 which is 1980 degrees then it will have 13 sides Consider the following rules that are applicable to all polygons:- (interior angles+360) divided by 180 = number of sides (number of sides -2) multiplied by 180 = sum of interior angles The above question is rather confusing because it implies that the interior angles of the polygon is the equivalent of twenty two right angles which is the same as 1980 degrees but working out how many sides the polygon has then the same rules apply. (1980+360)/180 = 13 sides (13 -2)*180 = 1980 degrees
Suppose the polygon has n sides Then sum of interior angles = (n-2)*180 degrees = 3960 degrees so n-2 = 3960/180 = 22 and so n = 24
To find the measure of each interior angle in a polygon when the sum of the angles is given, you divide the total sum by the number of angles in the polygon. If the sum of the interior angles is 3960, and the polygon is a hexagon (6 sides), each interior angle would measure 660 degrees (3960 ÷ 6 = 660). This is because the sum of the interior angles of a polygon with n sides is given by (n-2) * 180 degrees.
22 * * * * * NO. It is 24. The formula for an n-sided polygon is (n-2)*180 degrees which gives n-2 = 22. And then n = 24