9x2 + 25 has no rational factors. Its factorisation in the complex domain is:(3x + 5i)*(3x - 5i) where i is the imaginary square root of -1.
2x + 5 + 3x = 25 5x + 5 = 25 Subtract 5 from both sides: 5x = 20 Divide both sides by 5: x = 4
since y = 3x+1 we have y squared =(3x+1) squared x^2 + y^2 = 25 x^2 + (3x+1)^2=25 x^2 + 9x^2+ 6x+1 = 25 10x^2 + 6x + 1 = 25 10x^2 + 6x -24 = 0 solve x from quadratic formula x = 1.28 y = 3x + 1 = 4.83
6x
3x + 5 = -20. First, subtract 5 from both sides of the equation: 3x + 5 - 5 = -20 - 5; and simplify: 3x = -25. Then divide both sides by 3: 3x / 3 = -25 / 3; and simplify: x = -8 1/3 (or -8.33)
d/dx (3x+25)=3
9x2 + 30x + 25
10 -3x+8x = 25 -3x+8x = 25-10 5x = 15 x = 3
8x - 23= 3x + 2 +23 +23 8x=3x + 25 -3x -3x 5x=25 x=5 the answer is X=5
-2x^4+16 +2x^4+9-3x^5=-3x^5+25. There is no "answer" because there is no equation.
-3x + (-18) = 2x + 7 +18 +18 -3x = 2x +25 -2x -2x -5x = 25 ----- ----- -5 -5 x=-5 *------- equals a division line
If: 8x-4 = 3x+21 Then: 8x-3x = 21+4 => 5x = 25 => x = 25/5 Therefore: x = 5
That can be factored to (3x - 5)(3x - 5) or (3x - 5)2
x = 3
(x^2 - 3x + 5)(x^2 + 3x + 5)
25-7=18 18/3=6
3x + 1 = 25Subtract 1 from both sides:3x = 24Divide both sides by 3:x = 8