(x^2 - 3x + 5)(x^2 + 3x + 5)
(x2 + 1)(x2 - 2)
It is: (x-y)4
11y(y - 1)(2y^2 + 2y - 1)
106
X4 - 144 (X2 - 12)(X2 + 12) As there is no linear term I see no further factoring.
(x2 + 1)(x2 - 2)
It is: (x-y)4
b to the fourth power
(x2 - x + 1)(x2 + x + 1)
11y(y - 1)(2y^2 + 2y - 1)
"2 to the power of 4" is written "two to the fourth power", and "8 to the power of 2" is known as "eight squared". And, eight squared is greater than two to the fourth power. Eight squared is 64, and two to the fourth power is 16.
x^2(x - 4)(x + 4)
1
x to the 5th power times y to the fourth power
5x^2(4x - 5)(5x + 11)
106
If a number raised to the second power is squared and raised to the third power is cubed, I'm going to take a guess and say that a number raised to the fourth power is tesseracted.