4r+4g
It is (7 + a)r.
V = pi r^2*H & V = pi (4r)^2*h Equate pi r^(2)H= pi (4r)^2 h pi cancel down r^(2)H = (4r)^2h r^(2)*H = 16r^(2)*h 'r^(2) cancels down H= 16h h = H/16 This means is you increase the radius by '4 times' , then you reduce the height(H) by '16 times' in order to maintain the same volume.
2r + 2s = 50 2r - s = 17 therefore 4r - 2s = 34 Add so that you can eliminate one of the variables: 2r + 2s = 50 4r - 2s = 34 ---------------- 6r + 0s = 84 Solve for r: 6r = 84 r = 14 Substitute r into one of the original equations: 2(14) + 2s = 50 28 + 2s = 50 2s = 22 s = 11 Doublecheck with the other original equation: 2(14) - 11 = 28 - 11 = 17
2r + 7r - 6t - r + 7t = 8r + t
4r + 4 = 5r 4r - r = 3r 4r x r = 4r^2 4r/r = 4
Since 4R and R both contain a like term (R), you can combine them: 5R would be 4R plus R simplified
4r+4g
-13
(r + 2)(r + 2)
If you mean: 10+4r = 30 then it works out that r = 5
It is (7 + a)r.
It simplifies to: 2s+4R
r=8
-4r+6=14 isn't an inequality, its a linear equation. Anyway... -4r+6=14 (-6) -4r=8 (/4) -r=2 (x-1) r=-2
-2 - 2r or -2(1 - r)
so 26 = 4r so r = 6½