7n(n−1)
I don't know, just please helpp!
11
your equation is this 9N=63 9N/9=63/9 N=7 your answer is 7
All you have to do is divide 7 by 63. When you do that you get X=63/7. Divide those and you're left with X=9. Plug it back in 7(9)=63
63
7n = 91n = 91÷7n = 13
(10, 2)
7n = 28n = 28/7 = 4
7n + 1 = 6n + 8 7n=6n+7 (minus 1 from each side) n=7 (7n-6n equals n, you are left with n=7)
2 - 7n = 6therefore 7n = 2 - 6 = -4 and so n = -4/7 Then 5m + 7n = 6.4 becomes 5m - 4 = 6.4 so that 5m = 10.4 and then m = 10.4/5 = 2.08
7n = 7 divide by 7 on both sides n = 7
9n-2=7n+50 7n+9n=50+2 16n=52 n= 3.25
n(7n-3) = 0 n = 0 or n = 3/7
6m + 5n - 4m + 7n = 2m + 12n
N would equal 7
7n - 2 + 3n + 4 = 7n + 3n - 2 + 4 = 10n + 2 which can be simplified to 2(5n +1)