(x^2)-23x=0 Start by factoring out an x: (x)(x)-23x=0 x(x-23)=0 Set each quantity to 0 and solve for x: x(x-23)=0 x=0 x-23=0 x-23+23=0+23 x=23 Therefore x=0, x=23
(5 x 1024) + (7 x 1023) + (0 x 1022) + (0 x 1021) + (0 x 1020) + (0 x 1019) + (0 x 1018) + (0 x 1017) + (0 x 1016) + (0 x 1015) + (0 x 1014) + (0 x 1013) + (0 x 1012) + (0 x 1011) + (0 x 1010) + (0 x 109) + (0 x 108) + (0 x 107) + (0 x 106) + (0 x 105) + (0 x 104) + (0 x 103) + (0 x 102) + (0 x 101) + (0 x 100)
(1 x 10000000000000000) + (0 x 1000000000000000) + (0 x 100000000000000) + (0 x 10000000000000) + (0 x 1000000000000) + (0 x 100000000000) + (0 x 10000000000) + (0 x 1000000000) + (0 x 100000000) + (0 x 10000000) + (0 x 1000000) + (0 x 100000) + (0 x 10000) + (0 x 1000) + (0 x 100) + (0 x 10) + (0 x 1)
90,000,000 can be expressed in expanded notation with and without exponents:(9 x 107) + (0 x 106) + (0 x 105) + (0 x 104) + (0 x 103) + (0 x 102) + (0 x 101) + (0 x 100).(9 x 10000000) + (0 x 1000000) + (0 x 100000) + (0 x 10000) + (0 x 1000) + (0 x 100) + (0 x 10) + (0 x 1).
x^2 - 7x = 0 x(x - 7) = 0 x = 0 or x - 7 = 0 x = 0 or x = 7
(x^2)-23x=0 Start by factoring out an x: (x)(x)-23x=0 x(x-23)=0 Set each quantity to 0 and solve for x: x(x-23)=0 x=0 x-23=0 x-23+23=0+23 x=23 Therefore x=0, x=23
23 X 0 = 0
x=0
_//(2*2) - 4x - 7// * _//2// = 0 4* 12x - 7 * 122/100 = 0 28*12x * ((28*12)/122) = 0 (23/10 * x) * ((23/10 * x)/122) = 0 23/10 *x = 0 / ((23/10 *x)122) 23/10 *x = 0 23/x = 10 x = 2.3
(23/2)2 x2 - 23x = 0 x2 - 23x + (23/2)2 = (23/2)2 (x - 23/2)2 = (23/2)2 x - 23/2 = 23/2 x = 23/2 + 23/2 x = 23 Of course you could come to this solution much more easily by dividing the whole equation by x at the start. There really is no need to complete the square in this case: x2 - 23x = 0 x - 23 = 0 x = 23
To get the multiples of 23, just multiply 23 x 0, 23 x 1, 23 x 2, etc. - Or, starting with zero, add 23 at a time.
X + Y = 23 XY = 132 Y = 23-x xy = x (23-x) = 23x -x2= 132 x2-23x+132 = 0 (X-11)(x-12) = 0 X = 11 Y = 12
no, eg. 409 x 2 = 818 19 x 0 + 23 = 23
similar to a base 10 number... Ex: 100100 contains 6 place values. The left most is 1 x 26-1 , the second is 0 x 25-1 , and 0 x 24-1 ,1 x 23-1 ,0 x 22-1 ,0 x 21-1 . or 1 x 25 , 0 x 24 , 0 x 23 , 1 x 22 , 0 x 21 , 1 .
25
f : x -> 3x + 2 where 0 < x <23.
3x+8-31=0 Simplify it. 3x-23=0 Add 23 to both sides to get rid of the -23 3x=23 Divide both sides by 3 x=23/3 Simplfy the fraction x=9 2/3 So there we have it, x is nine and two thirds (or 9.6666...)