If: 2x2 = 4 Then: x = the square root of 2
An imperfect Square root is an number that doesn't have a two numbers that will equal to it's amount. For Ex. 2x2=4, there is something that equals 4, but what times what is thirteen, Nothing! Right! it only goes into itself once, that is an example of an imperfect square root, you have to find two numbers that will get you the closest to thirteen. Ask another question, for a better understanding. I hope this helps!
Yes, because 2x2 equals 4 and 4/2 equal 2
2x2 = 4 , Four . 2x2 = 4 , Four .
What is the solution set of 2x2 + x = 15
If: 2x2 = 4 Then: x = the square root of 2
x = square root of 3.
2x2 = 228 divide both sides by 2 x2 = 114 x = ±√114 by the square root property
2x2+9 = -412x2 = -41-92x2 = -50x2 = -25x = -5Check: (2*-52)+9 = -41Sorry, you can't have -5 as square root of -25.x = 5i, where i is the imaginary square root of -1
15,000 to the third power that equals pi plus 12 would make it the square root of 7
The square root of 4 is 2. (2x2 = 4).
Reading this as: 4x2-6=2x2 This implies that: -6=-2x2 3=x2 x=sqrt(3) and x=-sqrt(3) So x can equal plus or minus the square root of 3
2x2 - 3x + 7 = 0 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (3 plus or minus the square root of -47) divided by 4.x = 0.75 + 1.713913650100261ix = 0.75 - 1.713913650100261iwhere i is the square root of negative 1
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
If 2x2 + 3x + 9 = 0 then x = -0.75 - 1.984i or -0.75 + 1.984i where i is the imaginary square root of -1.
It works out that the centre of the circle is at (-0.5, 1.5) and its diameter is the square root of 28
46Improved answer:First rearrange this quadratic equation which will have two solutions :2x2-10x-6 = 0Simplify the equation by dividing all terms by 2:x2-5x-3 = 0Then by using the quadratic equation formula it will work out as:x = (5 + the square root of 37)/2or x = (5 - the square root of 37)/2