a2 + 62 = 122 a2 + 62 - 62 = 122 - 62 a2 = 144 - 36 a2 = 108 taking the square root of each side, we get a equal plus or minus the square root of 108, or plus or minus 6 times the square root of 3.
X = √63
7
If I have this correct you are asking x^2 + 10^2 = 12^2 Then x=6.633249507108
answer is p/5. problem: {[(p^2)-3p]/[(p^2)-6p+9]}/{20/(4p-12)}
4 squared minus 2 squared equals 12
5 or 12
It also equals 13 12.
X=-3
Twelve squared is a dozen dozen, or one gross. 122 = 12 times 12 = 144
-22 - 12 = -8
8.666666666666667
a2 + 62 = 122 a2 + 62 - 62 = 122 - 62 a2 = 144 - 36 a2 = 108 taking the square root of each side, we get a equal plus or minus the square root of 108, or plus or minus 6 times the square root of 3.
It is a quadratic equation in X, with two real roots.
x2 -x -12 = 0 (x+3)(x-4) = 0 Therefore, x = -3 & 4
3(x - 2)(x + 2)
The answer is 4 squared minus 2 squared as 4 squared is 16 minus 2 squared, which is 4, gives you 12 as an answer.