x^2+3x-18=0 (x+6)(x-3)=0
Find the remainder when f(x) is divided by (x - k) ƒ(x) = 2x3 + 3x2 + 4x + 18; k = -2 (x - k) = (x - (-2)) = (x + 2) x + 2 = 0 x = -2 By Remainder Theorem ƒ(x) = 2x3 + 3x2 + 4x + 18 ƒ(-2) = 2(-2)3 + 3(-2)2 +4(-2) + 18 = 2(-8) + 3(4) + 4(-2) +18 = -16 + 12 -8 +18 = 6 Thus, the remainder is 6
x + 10 = 18 18 - 10 = x 18 -10 = 8 x = 8
x2 + 36 = 20x so x2 - 20x + 36 = 0 so x2 - 2x - 18x + 36 = 0 or x(x - 2) - 18(x - 2) = 0 that is (x - 2)(x - 18) = 0 so x - 2 = 0 or x - 18 = 0 ie x = 2 or x = 18
It is (-1, 3).
If: x+18 = 20 Then: x = 2
I x=5 and y=2, then (5x5)=25 plus (9x2)=18. 25+18=43
6 x 2 + 6 + 18
2 + 2x = 18 2x = 18 - 2 2x = 16 x = 8
x^2 + 3x + 7 = 6x + 18 x^2 - 3x - 11 = 0
It is an equation and the value of x is 2
3x + 2 = x - 18 - 2 = - 2 3x = x - 20 - x = - x 2x = -20 /2 = /2 x = -10
x^2+3x-18=0 (x+6)(x-3)=0
You don't know that?! If x=3, then 6x is 6x3. So 18 plus 2 is.....20!!
you mean: x+3x+3=x+18 so x=5
8.
1