After 5 years, 20000 at 7% per annum compounded semiannually will be 20000*(1 + 0.5*7/100)2*5 = 20000*(1.035)10 = 28211.98
Total value = 20000*(1.06)2 = 22472 So interest = 2472
$5,249.54
2/3 of 200.00 is 133.33
It depends on how quickly / frequently the account compounds interestThe general equation for interest is this:A = P(1 + r/n)^(nt)Where A is the amount you will have at the end, P is how much you put in to begin with, r is the annual interest rate as a decimal. Also, n is the number of compounds per year and t is the number of yearsYou have given an A = 20,000You have given a t = 15 yearsYou have given an r = 0.05 (or 5%) aprYou want to find P, but you havent given me an n yetI will assume n=4. I make that assumption because that is very common. Most accounts compound four times a year. They call that "quarterly". Its a fair assumption. But if you want to be conservative try n=1, which is called "annually" and the account is compounded only once a year.Given the equation:A = P(1 + r/n)^(nt)Plug in what we know.20000 = P(1 + 0.05/4)^(4*15)20000 = P(1.0125)^(60)20000 / (1.0125)^(60) = PI get P = 9,491.35205, approximately.You will want to invest 9,491.36
20000/100 = 200
5000 dollars
18 percent of 20000 is 3600.
42% of 20000= 42% * 20000= 0.42 * 20000= 8,400
ANSWER: 380019% of 20000= 19% * 20000= 0.19 * 20000= 3800
200 as a percent = 20000%200= 200 * 100%= 20000%
To find 30 percent of a number, multiply it by 0.3. In this instance 0.3 x 20000 = 6000. Therefore, 30 percent of 20000 is equal to 6000.30% of 20000 = 600030% of 20000= 30% * 20000= 0.30 * 20000= 6000
It is 200.
3.75% of 20000 = 20000*3.75/100 = 750
400% of 20000 = 80,000
0.85% of 20000 = 20000*0.85/100 = 20000*0.0085 = 170
45% of 20,000= 45% * 20000= 0.45 * 20000= 9,000