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How much interest will 20000 earn in two years if invested at 6 percent compounded semiannually?
$5,249.54
How much interest is earned for the investment for 20000 for 2 years at 6 percent compounded annually?
Total value = 20000*(1.06)2 = 22472 So interest = 2472
How much must you invest at one time in order to accumulate 20000 in 15 years at 5 percent annual interest?
It depends on how quickly / frequently the account compounds interestThe general equation for interest is this:A = P(1 + r/n)^(nt)Where A is the amount you will have at the end, P is how much you put in to begin with, r is the annual interest rate as a decimal. Also, n is the number of compounds per year and t is the number of yearsYou have given an A = 20,000You have given a t = 15 yearsYou have given an r = 0.05 (or 5%) aprYou want to find P, but you havent given me an n yetI will assume n=4. I make that assumption because that is very common. Most accounts compound four times a year. They call that "quarterly". Its a fair assumption. But if you want to be conservative try n=1, which is called "annually" and the account is compounded only once a year.Given the equation:A = P(1 + r/n)^(nt)Plug in what we know.20000 = P(1 + 0.05/4)^(4*15)20000 = P(1.0125)^(60)20000 / (1.0125)^(60) = PI get P = 9,491.35205, approximately.You will want to invest 9,491.36
What is 1 percent of 20000?
1% 0f 20,000? (1/100)(20,000) = 200 or 0.01 x 20,000 = 200
What is the standard form for 80000000 7000000 600000 20000 400 30 2?
876200432
