18/6 = 3
3a + 4b - 5 - 1a + 7b + 3 - 1b 2a + 10b - 5 + 3 2a + 10b - 2
What is 18 divded 5
To solve this system of equations, you can use the method of elimination. First, multiply the first equation by 3 and the second equation by 2 to make the coefficients of 'a' the same. This gives you 6a + 21b = -3 and 6a - 14b = -10. Subtract the second equation from the first to eliminate 'a', resulting in 35b = 7. Dividing by 35 gives you b = 0.2. Substitute b back into one of the original equations to solve for 'a', yielding a = -2.
6
3
(6ab + 9b)/(2a + 3) = 3b(2a + 3)/(2a + 3) = 3b
We have, 2a + 24 = 30or, 2a = 30-24or, 2a = 6or, a = 6/2 = 3.Therefore, a equals 3 or simply a=3
2a+5a=3 7a=3 a=3/7 or .4286
(6a3 - 19a2 + 15a)/(2a - 3) = a(6a2 - 19a + 15)/(2a - 3) = a(2a - 3)(3a -5)/(2a -3) = a(3a - 5)
It is an equation and the value of b is 3
2a + 1 = 3subtract 1 from both sides2a = 2divide both sides by 2a = 1