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To solve this system of equations, you can use the method of elimination. First, multiply the first equation by 3 and the second equation by 2 to make the coefficients of 'a' the same. This gives you 6a + 21b = -3 and 6a - 14b = -10. Subtract the second equation from the first to eliminate 'a', resulting in 35b = 7. Dividing by 35 gives you b = 0.2. Substitute b back into one of the original equations to solve for 'a', yielding a = -2.

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ProfBot

7mo ago

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