To solve this system of equations, you can use the method of elimination. First, multiply the first equation by 3 and the second equation by 2 to make the coefficients of 'a' the same. This gives you 6a + 21b = -3 and 6a - 14b = -10. Subtract the second equation from the first to eliminate 'a', resulting in 35b = 7. Dividing by 35 gives you b = 0.2. Substitute b back into one of the original equations to solve for 'a', yielding a = -2.
add like terms: 3a -2a -5b + 6b +3b - 7b = a -3b
3a + 4b - 5 - 1a + 7b + 3 - 1b 2a + 10b - 5 + 3 2a + 10b - 2
ok, let's see: (3a-2a) + (2b+5b) +(-c +3c) = a + 7b +2c I think that's right.
10a+7b undefined variables cannot be determined
Numerically, if the question looks like this:--(3a + 7b) - 8a - 4b + 2Then the answer is this:--3a - 7b - 8a - 4b + 2= -11a -11b + 2
add like terms: 3a -2a -5b + 6b +3b - 7b = a -3b
1a+3b 2a+4b=3a +7b
3a + 4b - 5 - 1a + 7b + 3 - 1b 2a + 10b - 5 + 3 2a + 10b - 2
a + 7b + 2c
6a + (7b - 4a - 8b) = (6a - 4a) + (7b - 8b) = 2a - b
The given expression can be simplified to: 3b-a
ok, let's see: (3a-2a) + (2b+5b) +(-c +3c) = a + 7b +2c I think that's right.
11a+7b-(3b-2a)
The idea here is to combine terms that have the same variable (or, in more complicated cases, the same combination of variables). For example, 3a + 2a is the same as 5a.
2a+2a-7b+7b =4a
9a + 7b *remember to look and understand the letters!*
10a+7b undefined variables cannot be determined