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How do you factor 4x2-4x plus 2xy-2y?
4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) (4x + 2y)(x - 1).
What is 4xy minus 2y parenthesies x plus 4 parenthasies simplified?
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
4x2 - 4x plus 2xy - 2y?
4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) = (x - 1)(4x + 2y) = 2(x - 1)(2x + y)
Whats the factor from of 2xy-4x plus 8y-16?
2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .
Simplify 8 -x 2y you 2y - x?
8-x2y 8-2xy 2xy-8
Which of the followng is a example of a binomial is it 2y or 2xy?
Neither of those expressions is a binomial. [ 2y + 2xy ] is a binomial.
-2xy 3x plus 2y distribute?
There are not enough terms to distribute in any meaningful way.
What is the factor for 4x squared - 4x plus 2xy -2y?
2(x - 1)(2x + y)
(x2 + 2y) (x3 - 2xy + y3)?
(x^2 + 2y)(x^3 - 2xy + y^3) = x^2(x^3 - 2xy + y^3) + 2y(x^3 - 2xy + y^3) Now, let's distribute each term: = x^2 * x^3 - x^2 * 2xy + x^2 * y^3 + 2y * x^3 - 2y * 2xy + 2y * y^3 Now, simplify each term: = x^5 - 2x^3y + x^2y^3 + 2x^3y - 4xy^2 + 2y^4 Now, combine like terms: = x^5 + x^2y^3 - 4xy^2 + 2y^4 So, the expanded form of (x^2 + 2y)(x^3 - 2xy + y^3) is x^5 + x^2y^3 - 4xy^2 + 2y^4.
How do you solve 8 plus x2y?
i don't get that if it is 2xy +8 or 8 + 2xy then you can't solve or simplify it any further if it were 8 x 2y then you time the 8 by the 2 to get 16y
What is the answer to this math question 3xy-xy-2y plus 5y?
That equals 2xy + 3y which factors to y(2x + 3)
Factor of polynomial 2my plus 7x plus 7m plus 2xy?
You can find this by grouping the factors, then looking for common factors:2my + 7x + 7m + 2xy = (2my + 2xy) + (7x + 7m) = 2y(m+x) + 7(m+x).Since the factor m+x also happens to be a common factor, you can use the distributive law once more: 2y(m+x) + 7(m+x) = (2y+7)(m+x).Sometimes you have to try several possibilities; and of course, not all polynomials with 4 or more factors can be factored this way - or at all.
