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They cannot be combined, being unlike terms.

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13y ago
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Q: What is 2x³y² plus 7x²y²-3xy plus 2y³?
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How do you factor 4x2-4x plus 2xy-2y?

4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) (4x + 2y)(x - 1).


What is 4xy minus 2y parenthesies x plus 4 parenthasies simplified?

4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)


4x2 - 4x plus 2xy - 2y?

4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) = (x - 1)(4x + 2y) = 2(x - 1)(2x + y)


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2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .


Simplify 8 -x 2y you 2y - x?

8-x2y 8-2xy 2xy-8


Which of the followng is a example of a binomial is it 2y or 2xy?

Neither of those expressions is a binomial. [ 2y + 2xy ] is a binomial.


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There are not enough terms to distribute in any meaningful way.


What is the factor for 4x squared - 4x plus 2xy -2y?

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(x2 + 2y) (x3 - 2xy + y3)?

(x^2 + 2y)(x^3 - 2xy + y^3) = x^2(x^3 - 2xy + y^3) + 2y(x^3 - 2xy + y^3) Now, let's distribute each term: = x^2 * x^3 - x^2 * 2xy + x^2 * y^3 + 2y * x^3 - 2y * 2xy + 2y * y^3 Now, simplify each term: = x^5 - 2x^3y + x^2y^3 + 2x^3y - 4xy^2 + 2y^4 Now, combine like terms: = x^5 + x^2y^3 - 4xy^2 + 2y^4 So, the expanded form of (x^2 + 2y)(x^3 - 2xy + y^3) is x^5 + x^2y^3 - 4xy^2 + 2y^4.


What is x times 2y?

2xy


How do you solve 8 plus x2y?

i don't get that if it is 2xy +8 or 8 + 2xy then you can't solve or simplify it any further if it were 8 x 2y then you time the 8 by the 2 to get 16y


What is the answer to this math question 3xy-xy-2y plus 5y?

That equals 2xy + 3y which factors to y(2x + 3)