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1). y = 12). y = -4x3). y = -12xA "solution" is a pair of numbers ... one for 'x' and one for 'y' ... that makes the statements true.There is no solution for the group of all three equations.The solution for #1 and #2 taken together is (-1/4 , 1).The solution for #1 and #3 taken together is (-1/12 , 1).The solution for #2 and #3 taken together is (0, 0).
It is an equation of a straight line.
2x + y = 3 and y = 5x - 11 1) Plug the second equation for y into the first 2) 2x + (5x - 11) = 3 3) Solve for X 4) 7x = 14 5) x = 2 6) Plug X into either equation to get Y 7) 2(2) + y = 3 8) y = -1
If "equations-" is intended to be "equations", the answer is y = -2. If the first equation is meant to start with -3x, the answer is y = 0.2
Put the equation in this form: y=mx+b. Then m will be the slope. 2x3y+6=0 2x3y=-6 3y=-6/2x y=-2/2x y=-1/x This equation does not describe a straight line, but rather, it describes a curve.
x^2y(2x + y)
If: y+15 = 11 Then: y = -4
6-y equals 17x = -11
You can set this problem up like this: 48/4 = y/11 Cross multiply 48*11 = 4y 528 = 4y 528 divided by 4 = 132 So when w equals 11 y equals 132
11
y=11
If: y+5 = 11 Then: y = 6
If: y+15 = 11 Then: y = -4
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How do you add 2x plus 3y equals 18 in 5x-y equals 11
-11