1). y = 1
2). y = -4x
3). y = -12x
A "solution" is a pair of numbers ... one for 'x' and one for 'y' ... that makes the statements true.
There is no solution for the group of all three equations.
The solution for #1 and #2 taken together is (-1/4 , 1).
The solution for #1 and #3 taken together is (-1/12 , 1).
The solution for #2 and #3 taken together is (0, 0).
No solution. Multiply second equation by 3 and get 12x + 6y = 0 but already stated 12x + 6y = 9...
{-1,-2}
3 |4x-10| = 18 |4x-10|=6 4x-10 = 6 4x-10=-6 4x=16 4x=4 x=4 x=1
4x2-4x-3 = 0 (2x-3)(2x+1) = 0 x = 3/2 or x = -1/2
4x + 3y = -5 (Eq 1); 3x + 5y = -12 (Eq 2) Eliminate x Eq 1 times 3: 12x + 9y = -15 Eq 2 times 4: 12x +20y = -48 Subtract Eq 1 from Eq 2 11y = -48-(-15) ie 11y = -33 y = -3 Substitute in Eq 1: 4x - 9 = -5, ie 4x = 4 so x = 1 Check in Eq 2: (3 x 1) + (5 x -3) = 3 - 15 = -12. QED
No solution. Multiply second equation by 3 and get 12x + 6y = 0 but already stated 12x + 6y = 9...
8x-1=23-4x 12x=24 x=2
8x-1 = -4x+23 8x+4x = 23+1 12x = 24 x = 2
4x² - 12x + 9 = 5 → 4x² - 12x + 4 = 0 → x² - 3x + 1 = 0 → x = (-(-3) ±√((-3)² - 4×1×1))/(2×1) → x = (3 ±√5)/2 → x = (3 + √5)/2 or x = (3 - √5)/2
Y=4, X=1
2x - 3y = -1 Eq.1y = -4x + 24 Eq.2Put the value of Eq.2 on Eq.22x - 3(-4x + 24 ) = -12x + 12x -72 = -114x -72 = -114x = 72-114x = 71x= 71/14 .............. X = 5.07
If 4x - 1 = -5, then adding 1 to each side gives 4x = -4 and dividing, x = -1
1: 12x - 9y = 6 2: 12x + 20y = 64 Subtract 1 from 2: 29y = 58 y = 2. So does x.
OK, SO 4x = 12x + 32.SO 4x -12x-12x-12x+32 (subtract 12x from each side to get x on one side)SO -8x = 32 (simplify)SO -1 (-8x) = 32 (-1) (multiply each side by -1)SO 8x -32 (simplify)SO 8x / 8 = -32/8 (divide each side by eight (8) to get ""X"" by itself)SO x= -4SO x = -4.Does that help?Hope that helps!
1/2 or .5
x=2/7
10x-7y=-110x+1=7y-2x -10x-1=-25-12x-1=-25-12x=-24x=-24/-12x=210(2)-7y=-120-7y=-121=7y21/7=yy=3