(2x + 3)(2x + 3)
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
4x2 plus 3=11
I assume you mean factors for 4x2+10x+6.(2x+3)(2x+2).
No, it has factors... 4x2 + 8x -21 = (2x+7)(2x-3)
(2x + 3)(2x + 3)
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).
4x2 - 2x - 3 = 0 (2x + 1)(2x - 3) = 0 x = -(1/2) or (3/2)
(2x + 3)(2x - 1)
4x2 plus 3=11
This is how I did it:8x3+4x2+6x+3[8x3+4x2]+[6x+3][(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:(2x+1)(4x2+3)
I assume you mean factors for 4x2+10x+6.(2x+3)(2x+2).
No, it has factors... 4x2 + 8x -21 = (2x+7)(2x-3)
Only if the value of c is 9 because:- 4x2+12x+9 = (2x+3)(2x+3)
4x2 - 12x + 9 = 4x2 - 6x - 6x + 9 = 2x(2x - 3) - 3(2x - 3) = (2x - 3)(2x - 3) or (2x - 3)2
(3+2x)*(3-2x) = 9 - 4x2 [remember that (a+b)*(a-b)=a2 - b2]