x^(-5/3) = 4 1/x^(5/3) = 4 x^(5/3) = 1/4 [x^(5/3)]^(3/5) = (1/4)^(3/5) x = 1/4^(3/5) or, x = 4^(-3/5) Check: x^(-5/3) = 4 [4^(-3/5)]^(-5/3) = 4 ? 4 ^(15/15) = 4 ? 4^1 = 4 ? 4 = 4
x-4x=5 (1)x-(4)x=5 (-3)x=5 x= 5/(-3) x= -5/3
3x + 4y = 5To find the x-intercept, let x = 03(0) + 4y = 54y = 5y = 5/4The line passes through (0, 5/4), so y-intercept is 5/4.To find x-intercept, let y = 03x + 4(0) = 53x = 5x = 5/3The line passes through (5/3, 0), so x-intercept is 5/3.Plot (0, 5/4) and (5/3, 0). Draw a straight line through them.Or,3x + 4y = 53x - 3x + 4y = 5 - 3x4y = -3x + 54y/4 = (-3x + 5)/4y = (-3/4)x + 5/4So the slope will be -3/4 and the y-intercept is 5/4; (0, 5/4)We find the x-intercept when y = 0, so0 = (-3/4)x + 5/40 - 5/4 = (-3/4)x + 5/4 - 5/4-5/4 = (-3/4)x(-5/4)/(-3/4) = [(-3/4)x]/(-3/4)5/3 = x ; (5/3, 0)Thus, the line passes through the points (0, 5/4) and (5/3, 0).
(8 - 3) x (4 - 3) = 5 x 1 = 5
The LCM is 60. 5 = 5 x 1 2 = 2 x 1 3 = 3 x 1 4 = 2 x 2 Using the highest exponent of each prime, the LCM is 5 x 3 x 4 = 60
x^(-5/3) = 4 1/x^(5/3) = 4 x^(5/3) = 1/4 [x^(5/3)]^(3/5) = (1/4)^(3/5) x = 1/4^(3/5) or, x = 4^(-3/5) Check: x^(-5/3) = 4 [4^(-3/5)]^(-5/3) = 4 ? 4 ^(15/15) = 4 ? 4^1 = 4 ? 4 = 4
No, multiplication is associative. 5 x (4 x 3) = 4 x (5 x 3) = 3 x (5 x 4) = 5 x 4 x 3 = 60
3/4 x 4/5 = 12/20 = 6/10 = 3/5 or three fifthsNotice that the fours cancel out. Think about writing it as:3 x (1/4) x 4 x (1/5) = 3 x [(1/4) x 4] x (1/5) = 3 x [1] x (1/5) = 3 x (1/5) = 3/5.
3/5 x 5/12 x 4/15 = 3 x 5 x 4/5 x 12 x 15= 5 x (3 x 4)/5 x 12 x 15= 1/15
[(7+3)/(x+4)] / [(x-5)/(2-4)] =[(7+3)/(x+4)] * [(2-4)/(x-5)] =[10*(x-5)] / [-2*(x+4)] =-5*[(x-5)/(x+4)]
4 times 3 over 5 = 12/5= 4 * 3/5= 4/1 * 3/5= 12/5
Let the required number be x. 2/3 /x=4/5 x=4/5*3/2 x=6/5
1/4 x 5/3 = 5/12 5/12 x 3/4 = 5/16
If your expression is 5x + 4 = ? and x = 3, then the answer is 19. If the expression is 5(x + 4) = ? and x = 3, then the answer is 35.
4 x 2 x 3 x 5 = 120
x-4x=5 (1)x-(4)x=5 (-3)x=5 x= 5/(-3) x= -5/3
5*-4*-3 = 60