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They are 2 terms of an algebraic expression in the form of: 3b -c
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A is 3 times as large as b and 16 degrees larger than c what is the measure of each angle?
I suppose your talking about a triangle. The angles of a triangle add up to 180 degrees. So A + B + C = 180 If A is three times the size of B and if A is C + 16 degrees Then (3B) + B +(3B - 16) = 180 So, let's remove the brackets..... 3B + B + 3B - 16 = 180 Add the Bs and move the 16 to the other side of the equation... 7B = 180 + 16 7B = 196 B = 196 / 7 B = 28 So now we know B we can work out the other angles... A = 3B = 3 x 28 = 84 C = A - 16 = 84 - 16 = 68 A = 84 B = 28 C = 68 ----- Sum 180
What is an expression for the quotient of 3b and 4.5?
the quotient is the answer to a division problem, so the quotient of 3b and 4.5 is 3b/4.5
What is the answer to 2a x 3b?
2a x 3b = 6ab
What is 3B cubed?
3B cubed = 33*B3 = 27B3
2A plus 3B times 2A - 3B?
2A plus 3B times 2A - 3B = 4A2 - 9B2; this is an example of the general formula (a + b)(a - b) = a2 - b2.
How do you solve for b when a equals 3b-c?
a = 3b - c a + c = 3b - c + c a + c = 3b (a + c)/3 = 3b/3 ( a + c ) / 3 = b Do your homework.
What is the solution for -3b plus ac equals c-4 for c?
-7
What is 16a plus 3b-c-5a plus 3b plus 7c plus a equals?
12a + 6b + 6c = 6(2a + b + c)
Can 9a - 3b plus c be simplified?
12
What is b plus b plus b plus c plus c plus c plus c?
b+b+b+c+c+c+c =3b+4c
6b squared minus 3b divided by 3b?
6b^2 - 3b / 3b 6b^2 - 1 or ( 6b^2 - 3b) / 3b = 2b - 1 Or (6b^2 - 3b ) / 3b = 3b(2b - ) / 3b = 2b - 1
What is 3b squared minus 3b?
3b2 - 3b = 3b(b - 1)
B plus b plus b plus c plus c plus c plus c equals?
b + b + b + c + c + c + c = 3b + 4c
What is 4a plus 3c-2b-c plus a-b?
4a + 3c - 2b - c + a - b = 5a - 3b + 2c
A is 3 times as large as b and 16 degrees larger than c what is the measure of each angle?
I suppose your talking about a triangle. The angles of a triangle add up to 180 degrees. So A + B + C = 180 If A is three times the size of B and if A is C + 16 degrees Then (3B) + B +(3B - 16) = 180 So, let's remove the brackets..... 3B + B + 3B - 16 = 180 Add the Bs and move the 16 to the other side of the equation... 7B = 180 + 16 7B = 196 B = 196 / 7 B = 28 So now we know B we can work out the other angles... A = 3B = 3 x 28 = 84 C = A - 16 = 84 - 16 = 68 A = 84 B = 28 C = 68 ----- Sum 180
How do you find distance from an origin to a point?
plot point c so its distance from the origin is 1
What is the highest common factor for 3b and 9b?
Since 3b is a factor of 9b, it is automatically the GCF.
