If you mean: 2x+7y = -1 and 4x-3y = -19 then by substitution x = -4 and y = 1
4x + 3y - 2x - 7y2x - 4y
The derivative of 2x2 + 4x + 8 is 4x+4.
x = -½
x - 2
(4x - 7y)(4x + 7y)
33
-4x=7y-28 -4x+28=7y -4x/7+4=y A line with a y-int of 4 and a slope of -4/7
8x - 7y + 6
4x^(2) + 28xy + 49y^(2) -> (2x)^(2) + 28xy + (7y)^2 Split into brackets ( 2x + 7y)(2x + 7y) If you applyuFOIL you will find toy come to '28xy'. The clue to this problem is to note that '4' ^ '49' are both squared numbers.
6x plus 4y
4x+7y
9x + 3y + 5z - 5x + 4z - 7y = 4x - 4y + 9z
If the equations are 8x + 7y = 37, and 2y = 4x -2 then the answer is yes.
y^2 + 7y + 12 = (y+4)(y+3)
It is: 4x squared
y-5x