If: 4x+(-12) = 8 then 4x = 20 and x = 5
x=5
Only if 4 dollars plus 4 dollars equals 8 dollars.And if you had another 4x, you'd have a dozen-x.
Simplify 4x + 3 = 2x + 8 2x = 5 x =2½
2y = 4x - 16 5y = 4x + 8 Subtract the first equation from the second: 3y = 24 so that y = 8 Substitute this into the first equation: 16 = 4x - 16 ie 32 = 4x so that x = 8 So the solution is (8, 8)
If: 4x+(-12) = 8 then 4x = 20 and x = 5
8+7x = 20+3x 7x-3x = 20-8 4x = 12 x = 3
4x+32=-4x+16x4x+32=12x-4x -4x32=8x/8 /84=x
x = 1 and y = 6 so the lines intersect at the point (1, 6)
Add 12 to each side: 4x + 6x = 20 ie 10x = 20 so x = 2
9x + 8 = 4x + 23Subtract 8 from both sides9x = 4x + 15Subtract 4x from both sides5x = 15Divide both sides by 5x = 3
4x + 8 + 7x + 12 = 11x + 20
x=5
8 + 4x - x = 8 3x = 8 - 8 x = 0
4x+5=7x-8 the ansewr is 3.25
-4x + 8 = -4 -4x + 8 - 8 = -4 -8 -4x = -12 -4x/-4 = -12/-4 x = 3
I am having difficulty understanding your question. 12 + 20 = 10 is obviously false (12 + 20 = 32).If 4x + 14 = 2x + 30, then x must equal 8.